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3 years ago

I dont know how to do this

Mathematics

1 answer:

Kipish [7]3 years ago

4 0

So what you're going to do is just multiply how you were normal to play multiply the numerator times the other numerator then multiply the denominator's and that should get you your answer and then you can try and simplify it by finding if it can be divided equally then see if it is bigger or smaller

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The equation of a circle is (x−11)2+(y+15)2=144 .<br><br> What is the circle's radius?

yuradex [85]

The equation of a circle is (x-h)^2+(y-k)^2=r^2, where (h,k) is the center and r is the radius.
To find the radius, we would find the square root of 144, which is 12.
r=12

:)

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3 years ago

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If one side of a square notebook measures 20 cm, what is the area of the front cover of the notebook?

jarptica [38.1K]

Answer:

400 cm squared

Step-by-step explanation:

Since a square has all equal sides, this would mean the the all the other sides are 20 as well. To get the area, you would just multiply 20 by 20 to get 400. :)

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2 years ago

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What is a fraction equivalent to -6/1

pashok25 [27]

Answer:

-18/3

Step-by-step explanation:

Multiply the denominator and numerator by the same whole number.

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2 years ago

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What is the nth term rule of the linear sequence below?<br>13, 7, 1, -5, -11,...

vredina [299]

Sry I don’t know try Socratic

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2 years ago

Use the tangent identity to

Lunna [17]

Answer:

$tan(x)=\frac{44\sqrt{89}}{89}$

Step-by-step explanation:

tan is defined as: $tan(x)=\frac{opposite}{adjacent}$

sin is defined as: $sin(x)=\frac{opposite}{hypotenuse}$

cos is defined as: $cos(x)=\frac{adjacent}{hypotenuse}$

We can also define tan as: $tan(x)=\frac{sin(x)}{cos(x)}$

because plugging in the definitions of sin and cos in we get: $tan(x)=\frac{(\frac{opposite}{hypotenuse})}{(\frac{adjacent}{hypotenuse})}\\\\tan(x)=\frac{opposite}{hypotenuse}*\frac{hypotenuse}{adjacent}\\\\tan(x)=\frac{opposite}{adjacent}$

which you'll notice is the original definition of tan(x)

So using this definition of tan(x) we can use the givens sin(x) and cos(x) to find tan(x)

$sin(x)=\frac{44}{45}\\\\cos(x)=\frac{\sqrt{89}}{45}\\\\tan(x)=\frac{sin(x)}{cos(x)}$

plugging in sin(x) and cos(x) we get:

$tan(x)=\frac{\frac{44}{45}}{\frac{\sqrt{89}}{45}}\\\\tan(x)=\frac{44}{45}*\frac{45}{\sqrt{89}}\\\\tan(x)=\frac{44}{\sqrt{89}}$

We usually don't like square roots in the denominator, and from here we want to rationalize the denominator which we do by removing the square root from the denominator.

We can do this by multiplying the fraction by: $\frac{\sqrt{89}}{\sqrt{89}}$ which doesn't change the value of the fraction since it simplifies to 1, but it gets rid of the square root in the denominator

$tan(x)=\frac{44}{\sqrt{89}}*\frac{\sqrt{89}}{\sqrt{89}}\\\\tan(x)=\frac{44\sqrt{89}}{89}$

5 0

8 months ago