I dont know how to do this

Mathematics

1 answer:

Kipish [7]3 years ago

4 0

So what you're going to do is just multiply how you were normal to play multiply the numerator times the other numerator then multiply the denominator's and that should get you your answer and then you can try and simplify it by finding if it can be divided equally then see if it is bigger or smaller

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Mr .Baker has baked some muffins. If he packs them in boxes of 4, he will have 3 left over. If he packs them in boxes of 5, he w

babunello [35]

Answer:

$\boxed{43}$

Step-by-step explanation:

I think the easiest way to solve this problem is by brute force: trial and error.

We must find numbers that when divided by

4 leave 3 (4n + 3)
5 leave 3 (5n + 3)
6 leave 1 (6n + 1)

Here is a list of multiples of the integer n that satisfy the three conditions. $\begin{array}{c|ccc}\mathbf{n} & \mathbf{4n+ 3} & \mathbf{5n + 3} & \mathbf{6n + 1}\\1 & 7 & 8 & 7\\2 & 11 & 13 & 13\\3 & 15 & 18 & 19\\4 & 19 & 23 & 25\\5 & 23 & 28 & 31\\6 & 27 & 33 & 37\\7 & 31 & 38 & \mathbf{43}\\8 & 35 & \mathbf{43} & 49\\9 & 39 & 48 & 55\\10 & \mathbf{43} & 53 & 61\\\end{array}\\\text{The only number that is common to all three lists is $\mathbf{43}$.}\\\text{The smallest possible number of muffins Mr. Baker could have baked is $\boxed{\mathbf{43}}$.}$