3 years ago

How many solutions are possible for the equation 5(x-3)=7x-2(x+)1

1 answer:

5 0

5(x-3)= 7x-2(x+)1

5x - 15 = 7x - 2x + 1

5x - 15 = 5x + 1

-5x -5x

- 15 = 1

NO SOLUTIONS because -15 is not equal to 1

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