This is a problem i struggle wioth help ples

Mathematics

2 answers:

AlexFokin [52]3 years ago

7 0

Answer:

( 9,6 ) and (22,15)

Step by step explanation:

both y and x are going up by twos, so for the first part of the problem, you have to go to y= 6 and follow the line until you hit a point. the point is at 9 because the point is in between 8 and 10, and for coordinates x always goes first (x,y)

for the second part you go up tp y= 15 and follow the line until the hit the graphed line, which is at x =22

Anastasy [175]3 years ago

3 0

The coordinates for the first question is (9,6)
The second question- You could follow the x axis to where 15 balloons would be then follow straight up the graph to hit a point on the line and see where that point would be on the y axis.

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Véronique set a school record for most points in a single basketball game when her team scored 48 points. The six other players

Olenka [21]

Answer:

Step-by-step explanation:

3.5x6= 21

you would do 3.5x6 because they scored 3.5 each so then all together its 21 and 48-21=27 so Veronique scored 27 points

6 0

3 years ago

Prove the segments joining the midpoint of consecutive sides of an isosceles trapezoid form a rhombus. use the distance formula

riadik2000 [5.3K]

In order to prove this, we have to put the trapezoid to the coordinate system. In the attached photo you can see how it has to be put. The coordinates for the vertices of trapezoid written according to the midpoint principle. By using the distance between two points formula, we can find the coordinates for the vertices of the rhombus.
$D_{x} = \frac{-2b-2a}{2}=-b-a$ and $D_{y}= \frac{2c+0}{2}=c$ . The coordinates of D is $(-b-a, c)$
$E_{x} = \frac{-2b+2b}{2}=0$ and $E_{y}= \frac{2c+2c}{2}=2c$ . The coordinates of E is $(0,2c)$
Since we have the reflection in this graph, the coordinates of F is $(b+a, c)$
And the coordinates of G is (0,0).

Using the distance formula, we can find that
$DE= \sqrt{(-b-a)^{2}+ c^{2}}=\sqrt{(b+a)^{2} + c^{2}}$
$EF= \sqrt{(b+a)^{2} + c^{2} }$
$GF= \sqrt{(b+a )^{2} + c^{2} }$
$DG= \sqrt{(b+a)^{2}+ c^{2}$

Since all the sides are equal this completes our proof. Additionally, we can find the distances of EG and DF in order to show that the diagonals of this rhombus are not equal. So that it is not a square, but rhombus.