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Karo-lina-s [1.5K]
3 years ago
14

How do you find 3 (x-2)^2

Mathematics
1 answer:
lora16 [44]3 years ago
3 0
3 (x-2)^2
3 (x^2-2^2)

3x^2-12




We can have the basic inequalities and equalities’ sign. (>, =, <). 
These three set of symbols can discern, describe and explain the relationship between of numbers. These signs are used varying in many mathematical operations to explain and find discrepancy between value, sets of values or numbers in single and equitable category. 
Examples includes
 6 > 5; 6 is greater than 5; 5 is less than 6
 1 > -1; -1 is less than 1; 1 is greater than -1 
<span>-2 = -2; -2 is equal to -2  <span> </span></span>

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The longer leg of a right triangle is 4 more than the short leg. The hypotenuse is eight less than the sum of the 2 legs.
Crazy boy [7]

Answer:

SteLet a = short leg of the right triangle, b = the longer leg, and c = the hypotenuse.

The longer leg of a right triangle is 4inches longer than the shorter leg: b = a + 4

The hypotenuse is 8inches longer than the shorter leg:  c = a + 8

 

Use the Pythagorean Theorem:

 

a2 + b2 = c2

a2 + (a+4)2 = (a+8)2

a2 + a2 + 8a + 16 = a2 + 16a + 64

a2 - 8a - 48 = 0

 

Factors to:

 

(a-12)(a+4) = 0

a = 12, -4

 

Since we can't have a side of -4, a = 12

Shorter Leg = 12 inches

Longer Leg = 12 + 4 = 16 inches

Hypotenuse = 12 + 8 = 20 inches

6 0
3 years ago
X/8 = 13. what does X equal?​
In-s [12.5K]

Answer:

x equal 104

Step-by-step explanation:

since 8 needs to go into something 13 times we can multiply

8 x 13 to get

104

104 divided by 8

equals 13

8 0
3 years ago
Read 2 more answers
An oil tank in the shape of a cylinder has a diameter of 40 feet and a height of 32 feet. Which expression can be used to find t
Volgvan

The volume of a cylinder is pi*r^2*h

The radius is half the diameter, so 40/2=20, and the radius is 20 ft.

Plugging in: pi*20^2*32=pi*400*32=12800pi=40212.38597

So the volume is about 40212.4 ft^3 and the expression we used is pi*20^2*32

Hope this helped!

8 0
3 years ago
From our lesson, what is your difficulty in dealing with exponential expressions?
aleksandrvk [35]

Answer:

From the said lesson, the difficulty that I have been trough in dealing over the exponential expressions is the confusion that frequently occurs across my system whenever there's a thing that I haven't fully understand. It's not that I did not actually understand what the topic was, but it is just somewhat confusing and such. Also, upon working with exponential expressions — indeed, I have to remember the rules that pertain to dealing with exponents and frequently, I will just found myself unconsciously forgetting what those rule were — rules which is a big deal or a big thing in the said lesson because it is obviously necessary/needed over that matter. Surely, it is also a big help for me to deal with exponential expressions since it's so much necessary — it's so much necessary but I keep fogetting it.. hence, that's why I call it a difficulty. That's what my difficulty. And in order to overcome that difficulty, I will do my best to remember and understand well the said rules as soon as possible.

3 0
2 years ago
What is the cubed root of 216?
Ber [7]

Answer:

haha! You know the answer. Thanks tho!

Step-by-step explanation:

5 0
3 years ago
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