1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
andreyandreev [35.5K]
3 years ago
12

What is the percent change from 36 to 63

Mathematics
2 answers:
Jet001 [13]3 years ago
7 0
63 - 36 = 27
27 ÷ 0.75 = 36

That is a 75% change
viva [34]3 years ago
4 0
Initial number = 36
Final number = 63
Change in number = 63 - 36
                               = 27
Percentage change = (27/36) * 100
                                 = (3/4) * 100
                                 = 3 * 25
                                 = 75 percent
So the percentage change from 36 to 63 is 75%. I hope the procedure for solving is absolutely clear for you to understand. In future you can attempt such problems by following the procedure shown and you will require no further help from outside. Just be careful about the numerator and the denominator.
You might be interested in
A sample value that lies very far away from the majority of the other sample values is _____.
Elan Coil [88]
The answer to the missing word on the statement in this problem is an outlier.An outlier is a value that lies outside most of the other values in a set of data. It also means it is much smaller or larger than most of the values in a set.For example, in this given score set {24,29,2,32,88,33,26,28}. The scores 2 and 88 are outliers.
4 0
3 years ago
What is the value of 34 square
Oksi-84 [34.3K]

Question

What is the value of 34²

Answer:

1156

Step-by-step explanation:

just multiply 34 * 34 = 1156


5 0
3 years ago
a can has 50 marbles in it. Every hour, 7 marbles are taken out.After 4hours, how many marbles are left in the can?
KengaRu [80]
7×4=28

now subtract:

50-28=22

there are 22 marbles left in the can



hope this helped
5 0
4 years ago
Divide $150 into the ratio 2:5:3
pentagon [3]

Answer:

$30, $75, $45

Step-by-step explanation:

We can set up an equation, where x is an unknown value:

2x+5x+3x=150

10x = 150

x=15

Now that we know what x is, we can plug x in to solve for 2x, 5x, and 3x:

2x=2*15=30

5x=5*15=75

3x=3*15=45

Therefore, the answer is $30, $75, $45

5 0
3 years ago
Can someone help please i am really confused
Igoryamba

Answer:

so here we are told that angle CED is 39 degrees and in this diagram we have three angles the first one is Angle CED the next one is angle CEL and the last one is angle LED so angle c e l + angle LED is equals to angle c e d so in this case 3 x - 6 + x + 25 should be equal to 39 degrees collect the like terms 3 x + x + 25 - 6 is equals to 39 degrees 4X + 19 is equals to 39 cross the 19 over the equals sign that you have 4 x is equals to 39 + 19 4 x is equals to 68 divide both sides by 4 and x is equals to 17 then substitute replace where there is x with seventeen so in this case angle c e l will be 3 * 17 -6 we are multiplying 3 by 17 because it was 3 x and we got the value of x to be 17 so 3 * 17 is 51 -6 is 45 so angle CEL is 45 degrees you can do the same with the other angle that is angle LED and you get x to be 42

3 0
3 years ago
Other questions:
  • Can anyone help with this?
    14·1 answer
  • An "a" value of less than 1 produces a graph with an exponential decay . True or false ?
    8·1 answer
  • Only 15 and 16 are the one I'm confused on
    9·1 answer
  • What is the product of the binomials below? (3x+6)(4x+2)
    12·2 answers
  • 8/7 multiply by 7/10
    9·1 answer
  • Find the area of the parallelogram in the figure below.
    8·1 answer
  • HELP HELP HELP WHATR IS THE ANSWER PLEASE HELP ME ANSWER THIS CORRECTLY FOR 50 BRAINLIEST POINTS AND BRAINLIEST PLEASE
    6·1 answer
  • What is the missing length???
    9·1 answer
  • Given m//n find the value of x. see attachment.
    13·1 answer
  • What is 63 tenths less than 8.13?​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!