Answer:
Option A
Step-by-step explanation:
multiple each coordinate by 1/2
Answer:
1/3
Step-by-step explanation:
4/12÷3/3 = 1/3 ÷ 1 = 1/3
Answer:
y = Five-sixths x – 12
Step-by-step explanation:
In the picture attached, the given line is shown. Its slope is:
m = [6 - (-4)]/[12 - 0] = 5/6
The line that is parallel to the given line has the same slope.
A line with slope m that pass through (x1, y1) satisfies:
y - y1 = m(x - x1)
Replacing with m = 5/6 and point (12, -2):
y - (-2) = 5/6(x - 12)
y + 2 = 5/6x - 10
y = 5/6x - 10 - 2
y = 5/6x - 12
So you can do this multiple ways, I'll do this the way that I think makes sense the l most easily.
Cos (0) = 1
Cos (pi/2)=0
Cos (pi) =-1
Cos (3pi/2)=0
Cos (2pi)=1
Now if you multiply the inside by 4, the graph oscillates more violently (goes up and down more in a shorter period).
But you can always reduce it.
Cos (0)= 1
Cos (4pi/2) = cos (2pi)=1
Cos (4pi) =Cos (2pi) =1 (Any multiple of 2pi ==1)
etc...
the pattern is that every half pi increase is now a full period as apposed to just a quarter of one. That's in theory.
Now that you know that, the identities of Cosine are another beast, but mathematically.
You have.
Cos (2×2t) = Cos^2 (2t)-Sin^2 (2t)
Sin^2 (t)=-Cos^2 (t)+1..... (all A^2+B^2=C^2)
Cos (2×2t) = Cos^2 (t)-(-Cos^2 (t)+1)
Cos (2×2t)= 2Cos^2 (2t) - 1
2Cos^2 (2t) -1= 2 (Cos^2(t)-Sin^2(t))^2 -1
(same thing as above but done twice because it's cos ^2 now)
convert sin^2
2Cos^2 (2t)-1 =2 (Cos^2 (t)+Cos^2 (t)-1)^2 -1
2 (2Cos^2(t)-1)^2 -1
2 (2Cos^2 (t)-1)(2Cos^2 (t)-1)-1
2 (4Cos^4 (t) - 2 (2Cos^2 (t))+1)-1
Distribute
8Cos^4 (t) -8Cos^2 (t) +1
Cos (4t) =8Cos^4-8Cos^2 (t)+-1
