What is the equation of the line that is parallel to the given line and passes through the point (12, −2)? y = –Six-fifths x + 1
0 y = –Six-fifths x + 12 y = –Five-sixths x – 10 y = Five-sixths x – 12
2 answers:
Answer:
y = Five-sixths x – 12
Step-by-step explanation:
In the picture attached, the given line is shown. Its slope is:
m = [6 - (-4)]/[12 - 0] = 5/6
The line that is parallel to the given line has the same slope.
A line with slope m that pass through (x1, y1) satisfies:
y - y1 = m(x - x1)
Replacing with m = 5/6 and point (12, -2):
y - (-2) = 5/6(x - 12)
y + 2 = 5/6x - 10
y = 5/6x - 10 - 2
y = 5/6x - 12
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