What is the equation of the line that is parallel to the given line and passes through the point (12, −2)? y = –Six-fifths x + 1
0 y = –Six-fifths x + 12 y = –Five-sixths x – 10 y = Five-sixths x – 12
2 answers:
Answer:
y = Five-sixths x – 12
Step-by-step explanation:
In the picture attached, the given line is shown. Its slope is:
m = [6 - (-4)]/[12 - 0] = 5/6
The line that is parallel to the given line has the same slope.
A line with slope m that pass through (x1, y1) satisfies:
y - y1 = m(x - x1)
Replacing with m = 5/6 and point (12, -2):
y - (-2) = 5/6(x - 12)
y + 2 = 5/6x - 10
y = 5/6x - 10 - 2
y = 5/6x - 12
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Answer:
Step-by-step explanation:
Given: trapezoid RSTU with vertices R(-1, 5), S(1, 8), T(7, -2), and U(2, 0).
Plot these points on the coordinate plane. As you can see, lines RU and ST are parallel lines and segments ST and RU are bases of the trapezoid.
The median of the trapezoid (the middle line) passes through the midpoints of the sides RS and TU. Find these midpoints:
The equation of the line MN is
