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2 years ago

What is for 4/12÷3/3

Mathematics

1 answer:

satela [25.4K]2 years ago

4 0

Answer:

1/3

Step-by-step explanation:

4/12÷3/3 = 1/3 ÷ 1 = 1/3

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WILL GIVE BRAINLIEST AND 100 PNTS!! Which of the tables represents a function? Table A Input Output 5 3 5 2 4 1 Table B Input Ou

expeople1 [14]

Answer:

Table B

Step-by-step explanation:

Table A Input Output

5 3

5 2

4 1

Has an input that goes to 2 different outputs, not a function

Table B Input Output

1 2

3 2

5 3

one to one relation which is a function

Table C Input Output

0 0

1 2

1 3

Has an input that goes to 2 different outputs, not a function

Table D Input Output

4 2

4 3

4 4

Has an input that goes to 2 different outputs, not a function

4 0

2 years ago

What is the surface of a triangular prism 1 cm 1 cm 1.2 cm 1.2 cm 0.8 cm

Masja [62]

Answer:

dddddddd

Step-by-step explanation:

ddddddd

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2 years ago

Decide whether this situation is looking for the part, the percent, or the whole. 14 compact cars are 56% of the cars sold tha

bekas [8.4K]

Answer:percent

Step-by-step explanation: I don’t know

6 0

2 years ago

Read 2 more answers

Differentiate Functions of Other Bases In Exercise, find the derivative of the function.

WARRIOR [948]

Answer:

$\dfrac{dy}{dx} =\dfrac{2 x + 6}{ \log{\left (10 \right )}\left(x^{2} + 6 x\right)}$

Step-by-step explanation:

given

$y = \log_{10}{(x^2+6x)}$

using the property of log $\log_ab=\frac{log_cb}{log_ca}$ , and if c = $e$ , $\log_ab=\frac{ln{b}}{ln{a}}$ , we can rewrite our function as:

$y = \dfrac{\ln{\left (x^{2} + 6 x \right )}}{\ln{\left (10 \right )}}$

now we can easily differentiate:

$\dfrac{dy}{dx} = \dfrac{1}{\ln{10}}\left(\dfrac{d}{dx}(\ln{(x^{2} + 6x)})\right)$

$\dfrac{dy}{dx} = \dfrac{1}{\ln{10}}\left(\dfrac{2x+6}{x^{2} + 6x}\right)$

$\dfrac{dy}{dx} =\dfrac{2 x + 6}{ \log{\left (10 \right )}\left(x^{2} + 6 x\right)}$

This is our answer!

3 0

2 years ago

Read 2 more answers

Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

Correct answer:

A. I and II

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

Correct answer:

A. I and II

4 0

2 years ago