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ki77a [65]
3 years ago
15

Find a number that has four identical factors each factor must be greater than 1 and can have only 1 and itself as factors

Mathematics
1 answer:
Oksana_A [137]3 years ago
7 0
"Have only 1 and itself as a factor" is definition of prime

so each factor must be prime

let ssay 2
2 is prime

2^4=16
a number is 16
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Answer:

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Step-by-step explanation:

We need to find the find all the points having an x coordinate of 2 whose distance from the point (-2,-4) is 5.

A circle with center (-2,-4) and radius 5 represents all the points whose distance from the point (-2,-4) is 5.

Standard form of a circle is

(x-h)^2+(y-k)^2=r^2

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(x-(-2))^2+(y-(-4))^2=(5)^2

(x+2)^2+(y+2)^2=25

Now, put x=2.

(2+2)^2+(y+2)^2=25

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(y+2)^2=9

Taking square root on both sides.

y+2=\pm\sqrt{9}

y+2=\pm3

y+2=-3\text{ or }y+2=3

y=-5\text{ or }y=1

So, the y-coordinates of the points are -5 and 1.

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Andreyy89
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