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slamgirl [31]
3 years ago
11

Justin's football team has a phone tree in case a game is cancelled. The coach calls 2 players. Then each of those players calls

2 players, and so on. How many player will be notified during the 2nd round of calls?

Mathematics
1 answer:
kirill [66]3 years ago
7 0
<span>As the coach calls two players and those two players call two players each. Then total players called in second round of calls would be four. Which can be calculated by an equation.. 2^n Where n will the round in which the call would be there.</span>
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How would you convert 5 feet 6 inches to inches
zubka84 [21]
66 inches. Since 1 foot is equal to 12 inches, all you need to do is to multiply 5 with 12. The answer will be 60. Since 6 inches are already given for the answer, just add up 60 with 6 for you to get 66 inches which is equivalent to 5 feet 6 inches.
6 0
3 years ago
Jasmine is designing boxes she will use to ship her jewelry. She wants to shape the box like a regular polygon. In order for the
Naddik [55]

Answer:

The regular polygon that she should use is an equilateral  triangle

Step-by-step explanation:

The parameters given are;

Interior angles = 0.5 × Exterior angles

Exterior angles of a regular polygon = 360/n

Sum of interior angles of a regular polygon = (n - 2) × 180

Where n = the number of sides

Therefore, the sum of exterior angles of a regular polygon = 360°

Hence we have;

(n - 2) × 180 = 360/2 = 180

n - 2 = 180/180 = 1

n = 1 + 2 = 3 which is a three sided regular polygon or an equilateral triangle

Therefore, the regular polygon that she should use is an equilateral  triangle

3 0
3 years ago
The line tangent to the graph of g(x) = x^{3}-4x+1 at the point (2, 1) is given by the formula
Usimov [2.4K]

well, about A and D, I just plugged the values on the slope formula of

\bf \begin{array}{llll} g(x)=x^3-4x+1\\ L(x) = 8(x-2)+1 \end{array} \qquad \begin{cases} x_1=1.9\\ x_2=2.1 \end{cases}\implies \cfrac{f(b)-f(a)}{b-a}

for A the values are 8.01 and 8.0, so indeed those "slopes" are close. \textit{\huge \checkmark}

for D the values are -2.25 and 8.0, so no dice on that one.

for B, let's check the y-intercept for g(x), by setting x = 0, we end up g(0) = 0³-4(0)+1, which gives us g(0) = 1.

checking L(x) y-intercept, well, L(x) is in slope-intercept form, thus the +1 sticking out on the far right is the y-intercept, so, dice. \textit{\huge \checkmark}

for C, well, the slope if L(x) is 8, since it's in slope-intercept form, the derivative of g(x) is g'(x) = 3x² - 4, and thus g'(0) = -4, so no dice.

for E, do they intercept at (2,1)?  well, come on now, L(x) is a tangent line to g(x), so that's a must for a tangent. \textit{\huge \checkmark}

for F, we know the slope of the line L(x) is 8, is g'(2) = 8?  let's check

recall that g'(x) = 3x² - 4, so g'(2) = 3(2)² - 4, meaning g'(2) = 8, so, dice. \textit{\huge \checkmark}

6 0
3 years ago
1. If a triangle of area 95 square units has a height of length 19 units, calculate
Anna [14]
48 I believe :) pls like I need points
8 0
1 year ago
At the end of the current year, Accounts Receivable has a balance of $4,375,000; Allowance for Doubtful Accounts has a debit bal
Advocard [28]

Answer:

$226,300

Step-by-step explanation:

Given Allowance for Doubtful Accounts is estimated as $205,000 and Allowance for Doubtful Accounts has a debit balance of $21,300

#The  amount of the adjusting entry for uncollectible accounts is calculated as below:

Adjustment \ Cost=Allowance\ Doubtful\ Accounts +Doubtful \ Accounts \ Debit \ Balance\\\\=205000+21300\\\\\$226,300

Hence,  the amount of the adjusting entry for uncollectible accounts is $226,300

8 0
2 years ago
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