Answer:
5/ 18
Explanation:
Given :
List A: [20,10,20]
List B: [40,10,30,20,40,30]
Chance that number drawn from list A is larger than or equal to that drawn dlfrom list B.
If:
A = 20
B ≤ 20 : [10,20] = 2
A = 10
B ≤ 10 : [10] = 1
A = 20
B ≤ 20 : [10,20] = 2
Probability = Required outcome / Total possible outcomes
Hence,
required outcome = (2 + 2 +1) = 5
Total possible outcomes = 3C1 * 6C1 = (3 * 6) = 18
Hence,
chance that the number we drew from list A is larger than or equal to the number we drew from list B
= 5 / 18
Answer:
There is no need to make an algorithm for this simple problem. Just add the two numbers by storing in two different variables as follows:
Let a,b be two numbers.
c=a+b;
print(c);
But, if you want to find the sum of more numbers, you can use any loop like for, while or do-while as follows:
Let a be the variable where the input numbers are stored.
while(f==1)
{
printf(“Enter number”);
scanf(“Take number into the variable a”);
sum=sum+a;
printf(“Do you want to enter more numbers? 1 for yes, 0 for no”);
scanf(“Take the input into the variable f”);
}
print(Sum)
Explanation:
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Answer:
//C++ code for the cash register..
#include <iostream>
#include<vector> //including vector library
using namespace std;
int main() {
vector<float> cash; //declaring a vector of type float.
float item=2,cash_sum=0;
int counter=1;
while(item!=0)//inserting prices in the vector until user enters 0...
{
cout<<"Enter the price of item "<<counter<<" :"<<endl;
cin>>item;
counter++;
cash.push_back(item);//inserting element in the vector...
}
for(int i=0;i<cash.size();i++)//looping over the vector...
{
cash_sum+=cash[i];//summing each element..
}
cash_sum*=1.08;//adding 8% sales tax.
cout<<cash_sum;//printing the result....
return 0;
}
Explanation:
I have taken a vector of type float.
Inserting the price of each item in the vector until user enters 0.
Iterating over the vector for performing the sum operation.
Then after that adding 8% sales tax to the sum.
Printing the output at last.
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Answer:
The most operating system perform these task that can be given as:
Allocating RAM to open programs.
Creating and maintaining the FAT
.
Coordinating the interaction between hardware and software.
Displaying the GUI
.
Explanation:
The description of these task as follows:
- Allocating ram to open program: RAM stands for Random Access Memory in the operating system when we on the computer system so the operating system first load some file that use the ram because it is volatile memory. It works when the system is on.
- Creating and maintaining the FAT
: FAT stands for File Allocation Table. This file stored in the hard drive that usually support 12 or 16-bit cluster for insert data into FAT. This file is only used by the operating system for creating and manages files.
- An operating system works as an interface between computer hardware and the user. It is a System software that coordinates between hardware and software.
- Displaying the GUI: The term GUI stands for graphical user interface. It is a feature of operating systems that provide the GUI mode. In this mode, the user can understand things more easily.
