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3 years ago

Describe all of the acceptable ways to name a plane

Mathematics

2 answers:

mina [271]3 years ago

6 0

Answer:

One capital letter

Step-by-step explanation:

Otrada [13]3 years ago

5 0

A geometric plane can be named as a single letter, written in upper case and in cursive lettering, such as plane Q. A plane can also be named by identifying three separate points on the plane that do not form a straight line.

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60>5(6-2x) ok help me so I can get an answer

Dima020 [189]

Inequalities are used to represent unequal expressions

The solution to the inequality is: $x > -3$

<h3>How to determine the inequality solution</h3>

The inequality is given as:

60>5(6-2x)

Rewrite the inequality properly as:

$60>5(6-2x)$

Divide both sides of the inequality by 5

$12>6-2x$

Subtract 6 from both sides of the inequality

$6>-2x$

Divide both sides of the inequality by -2

$-3Rewrite the inequality as[tex]x > -3$

Hence, the solution to the inequality is: $x > -3$

Read more about inequalities at:

brainly.com/question/11234618

5 0

2 years ago

Find the GCF of 32, 64, and 96. The GCF is _______.

baherus [9]

Answer:

128

Step-by-step explanation:

If you multiply you get it.

7 0

3 years ago

Read 2 more answers

Find the length of the third side to the nearest tenth 6 and 9

oee [108]

Hello, i do believe that you are asking me to do pythagorean theorem.

I'm not too sure if we are solving hypotenuse or a/b so i'll do both.

$\boxed{\underline{Hypotenuse...}}\\\\\\A^2+B^2=C^2\\6^2+9^2=C^2\;\\36+81=117$

$\sqrt{117}=10.816\\Round-\;10.8$

$\boxed{\underline{a/b...}}\\\\\\A^2=C^2-B^2\\A^2=9^2-6^2\\A^2=81-36\\A^2=45\\\sqrt{45}= 6.708\\Round-\;6.7$

Hope it helps!

6 0

2 years ago

Show work only do those 32,34,36,38,40

Free_Kalibri [48]

Answer: see below

Step-by-step explanation:

$32)\quad \dfrac{3}{5}(x-12)>x-24$

3(x - 12) > 5(x - 24)

3x - 36 > 5x - 120

-5x -5x

-2x - 36 > -120

+36 +36

-2x > -84

÷ -2 ↓ ÷ -2

x < 42

Graph: ←------------o

34) 6[5y - (3y - 1)] ≥ 4(3y - 7)

6[5y - 3y + 1] ≥ 4(3y - 7)

6{2y + 1] ≥ 4(3y - 7)

12y + 6 ≥ 12y - 28

-12y -12y

6 ≥ -28

TRUE so the solution is All Real Numbers

Graph: ←-----------------------→

36) BC + AC > AB

4 + 8 - AB > AB

12 - AB > AB

+AB +AB

12 > 2AB

÷2 ÷2

6 > AB

AB < 6

$38)\quad \dfrac{1}{2}(y-16)\geq y+2\quad ;\text{claim}\ y\leq 20$

Check: let y = 16

then $\frac{1}{2}$ (16 - 16) ≥ 16 + 2

0 ≥ 18

FALSE so the claim is wrong

40) question not provided in the image so I cannot give a solution.

7 0

3 years ago

SOMEONE HELP ME!! PLEASE Solve the equation to find a positive value of c: 2 2 2 3 +4=c

stiv31 [10]

I think c would equal 7.

6 0

3 years ago