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3 years ago

For what values of b the relation R:{(b^2, 5), (5b, 6)} is not a function?

Mathematics

1 answer:

xenn [34]3 years ago

6 0

Answer:

B=5,0.

Step-by-step explanation:

It's not that hard. It's just that it might throw you off a bit with the R and the other things. Functions if you don't remember are where the coordinates don't have the same x and y. So since the y1 and y2 are different then to make it not a function, you have to make x1 and x2. To make it that b would have to be = to 5 and 0.

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Which statements are true about the ordered pair (10, 5) and the system of equations?

Alexeev081 [22]

Answer:

Step-by-step explanation:

We have the system of equations:

$\left\{\begin{array}{ll}2x-5y=-5 \\ x+2y=11\end{array}$

And an ordered pair (10, 5).

In order for an ordered pair to satisfy any system of equations, the ordered pair must satisfy both equations.

So, we can eliminate choices A and B. Satisfying only one of the equations does not satisfy the system of equations.

Let’s test the ordered pair. Substituting the values into the first equation, we acquire:

$2(10)-5(5)\stackrel{?}{=}-5$

Evaluate:

$20-25\stackrel{?}{=}-5$

Evaluate:

$-5\stackrel{\checkmark}{=} -5$

So, our ordered pair satisfies the first equation.

Now, we must test it for the second equation. Substituting gives:

$(10)+2(5)\stackrel{?}{=} 11$

Evaluate:

$20\neq 11$

So, the ordered pair does not satisfy the second equation.

Since it does not satisfy both of the equations, the ordered pair is not a solution to the system because it makes at least one of the equations false.

Therefore, our answer is C.

3 0

3 years ago

The sum of 6 consecutive integers is 204. what is the fourth number in this sequence?

zloy xaker [14]

Let $x$ by the smallest of the 6 integers. Then

$x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=204$

$\implies6x+15=204$

$\implies6x=189$

But 189 is odd, so it cannot be divisible by 6, which means $x$ is not an integer...

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Nana76 [90]

Answer:

i think the answer is 7

Step-by-step explanation:

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