Question 4 of 10

Question 2 Multiple Choice Worth 1 points)

likoan [24]

Answer:

Solution: means we replace 'x' with 'x+1' and we get g (x). Let us put x = 0 and then y = 0 to find two points on coordinate axis to easily plot the graph of g (x). Now, let us put y = 0 and find out x. So, second point is . Now, let us plot A and B then extend the line joining AB.

4 0

3 years ago

Find the coordinates of the turning point for the equation of the graph below y=x^2+14x+45

USPshnik [31]

Answer:

(- 7, - 4 )

Step-by-step explanation:

Given a quadratic in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the turning point is

x = - $\frac{b}{2a}$

y = x² + 14x + 45 ← is in standard form

with a = 1, b = 14 , then

x = - $\frac{14}{2}$ = - 7

Substitute x = - 7 into the equation and evaluate for y

y = (- 7)² + 14(- 7) + 45 = 49 - 98 + 45 = - 4

coordinates of turning point = (- 7, - 4 )

4 0

3 years ago

You start at (2, -4). You move up 4 units. Where do you end?

NeTakaya

Answer:

(2, 0)

Step-by-step explanation:

Hope This Helps! : )

7 0

3 years ago

Proof 1<br> Given: AB║CD , AD║CB<br> Prove: ΔABC ≅ΔCDA

lys-0071 [83]

<u>Statement Reason </u>

AB║CD , AD║CB Given

m∠BAC = m∠ACD Alternate Interior Angles

m∠ACB = m∠CAD Alternate Interior Angles

AC = AC Reflexive Property of Equality

ΔABC ≅ΔCDA ASA ≅

7 0

3 years ago

The length of a rectangle is eight more than twice its width. The perimeter is 96 feet. Find the dimensions of the rectangle

Debora [2.8K]

Answer:

The width of the rectangle is 14'8", and the length is 33'4"

Step-by-step explanation:

We're given two pieces of information:

The length is eight more than twice the width:

$l = 2w + 4$

The perimeter is 96 feet:

$p = 96$

We also need to apply one more piece of information that is not provided here, and that is the relationship between the perimeter of a rectangle, and it's length and width:

$p = 2l + 2w$

We can solve for w by plugging the other two values into the last:

$p = 2w + 2l\\96 = 2w + 2(2w + 4)\\96 = 2w + 4w + 8\\88 = 6w\\3w = 44\\w = \frac{44}{3}\\w = 14\frac{2}{3}$

Now we can find the length by plugging w into the first equation:

$l = 2w + 4\\l = 2(14\frac{2}{3}) + 4\\l = 29\frac{1}{3} + 4\\l = 33\frac{1}{3}$

One third of a foot is four inches, so the width is 14'8" and the length is 33'4"

To make sure our answer is correct, we should plug those numbers back into the area equation and see if we're right:

$p = 2l + 2w\\p = 2(33\frac{1}{3}) + 2(14\frac{2}{3})\\p = 66\frac{2}{3} + 29\frac{1}{3}\\p = 96$

So we know our answer's correct

8 0

3 years ago