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2 years ago

Insert one pair of brackets only to make the following statement correct 6 +5*10-8=16

Mathematics

1 answer:

jeka942 years ago

4 0

Answer:

6+5*(10-8)=16

Step-by-step explanation:

Using BODMAS multiplication takes precedence over addition and subtraction so as it stands it would be calculated as 6 + (5*10) - 8. To get the answer 16 it would be 6 + 5(10 - 8) Solving the brackets first, this gives 6 + (5*2) which gives 16.

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I need help solving problem 11.

Lunna [17]

Since triangle ABC is isosceles, then angles 1 and 9 are congruent.

4x + 3 = 9x - 47

-5x = -50

x = 10

m<1 = 4x + 3 = 40 + 3 = 43

m<1 = m<9 = 43

Triangle DBE is equilateral, so it is also equiangular.

m< 4 = m<5 = m<6 =60

Angles 3 and 8 are supplementary to congruent angles that measure 60 deg, so 180 - 60 = 120, so

m<3 = m<8 = 120

For angles 2 and 7, use the sum of the measures of the angles of a triangle is 180 deg.

m<1 + m<2 + m<3 = 180

43 + m<2 + 120 = 180

m<2 + 163 = 180

m<2 = 17

m<2 = m<7 = 17

4 0

3 years ago

Express the area of the entire rectangle.

Cloud [144]

Answer:

$\huge\boxed{A=x^2+12x+35}$

Step-by-step explanation:

The formula of an area of a rectangle:

$A=lw$

l - length

w - width

We have

$l=x+7\\\\w=x+5$

Substitute:

$A=(x+7)(x+5)$

Use FOIL (a + b)(c + d) = ac + ad + bc + bd

$A=(x)(x)+(x)(5)+(7)(x)+(7)(5)\\\\A=x^2+5x+7x+35$

combine like terms

$A=x^2+(5x+7x)+35\\\\A=x^2+12x+35$

7 0

2 years ago

Which of the following is a factor of 2xy+8x-8x-32

IrinaVladis [17]

If you simplify 2xy+8x-8x-32 you get 2xy-32

5 0

3 years ago

Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet

zmey [24]

Answer:

$\sin \theta = \dfrac{5}{13}$ and $\sec \theta = -\dfrac{13}{12}$

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

$hypotenuse^2=perpendicular^2+base^2$

$hypotenuse^2=(5)^2+(12)^2$

$hypotenuse^2=25+144$

$hypotenuse^2=169$

Taking square root on both sides.

$hypotenuse=13$

In a right angled triangle

$\sin \theta = \dfrac{opposite}{hypotenuse}$

$\sin \theta = \dfrac{5}{13}$

$\sec \theta = \dfrac{hypotenuse}{adjacent}$

$\sec \theta = \dfrac{13}{12}$

In second quadrant only sine and cosecant are positive.

$\sin \theta = \dfrac{5}{13}$ and $\sec \theta = -\dfrac{13}{12}$

6 0

3 years ago

Given a term and the common difference, find the explicit formula. 8. a(19) = 135 d = 15

Rasek [7]

The explicit formula is a(n) = 15(n – 10)

Solution:

Given, a term a(19) = 135 and common difference d = 15

We have to find the explicit formula.

Now, we know that, a(n) = a + (n – 1)d where a(n) is nth term, a is first term, d is common difference,

So, for a(19)

$\begin{array}{l}{\rightarrow a(19)=a+(19-1) 15} \\\\ {\rightarrow 135=a+18 \times 15} \\\\ {\rightarrow a=135-270} \\\\ {\rightarrow a=-135}\end{array}$

Now, we know that, an explicit formula is an expression for finding the nth term,

So, in our problem, expression for finding nth term is a + (n – 1)d

$\begin{array}{l}{\rightarrow-135+(n-1) 15} \\\\ {\rightarrow-135+15 n-15} \\\\ {\rightarrow 15 n-150} \\\\ {\rightarrow 15(n-10)}\end{array}$

Hence, the explicit formula is a(n) = 15(n – 10).

7 0

2 years ago