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Tanya [424]
3 years ago
14

Is x^2-49 a difference of two squares?

Mathematics
1 answer:
Svet_ta [14]3 years ago
4 0
Yes! To factor this, you would put it into expanded form: (x+7)(x-7). This is the only way to solve this and eliminate the x^1 term.
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12x12=144. Answer is 144 miles

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Jessica has an account with a credit union. Her account earns 2.5% simple interest yearly. Exactly a year and a half ago, she op
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<span>Ans: I = P*r*t = 900*0.023*1.5 = $31.50

I hope this help</span>
5 0
3 years ago
Please help !! Geometry homework. Will mark brainliest answer !
sergeinik [125]

For this case we have:


By trigonometric property we have:


Cosine(\alpha)=\frac{AdjacentLeg}{Hypotenuse}

Where:


Adjacent Leg = 12\\Hypotenuse = 13\\\alpha= x

Substituting:


Cosine(x)=\frac{12}{13}

Clearing x we have:


x =Cosine^{-1}(\frac{12}{13})

Thus, the equation is: x =Cosine^{-1}(\frac{12}{13})

Answer:


x =Cosine^{-1}(\frac{12}{13})


3 0
3 years ago
​ Quadrilateral ABCD ​ is inscribed in this circle.
Anna [14]
A quadrilateral, has 4 sides and its internal angles sum, add up to 360, now... you have 3 angles give.. .but we don't have C

so.. C is the difference of all the three angles from 360 or  \bf \measuredangle C=360-x-(2x+1)-148\implies \measuredangle C=360-x-2x-1-148   whatever that is, now, you'll get some value in x-terms

so.... now once we know what C is

you can if you want, do a search in google for "inscribed quadrilateral conjecture",  I can do a quick proof if you need one

but in short, for a quadrilateral inscribed in a circle, each pair of opposites angles are "supplementary angles", namely they add up to 180°

so.. what the dickens does all that mean?   well D+B=180 and A+C = 180

now. we know what A is, 2x+1
and by now, you'd know what C is from  360-x-2x-1-148

so... add them together then   and

\bf \begin{array}{cccclllll}&#10;A&+&C&=&180\\&#10;\uparrow &&\uparrow \\&#10;(2x+1)&+&(360-x-2x-1-148)&=&180&#10;\end{array}

solve for "x"


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zavuch27 [327]
You need to add 5d with 5d then add the d to it for it to get the length and the width
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