Admission cost to the fiar = $12.99.
Each ride cost = $1.75.
Let us assume number of rides = x.
a) Addimission charges + each ride cost *x <= Total money have.
We are given total money have = $35.
We can setup an inequality now
12.99 + 1.75*x <=35.
12.99 +1.75x <=35 is the required inequality.
b) Let us solve this inequality for x.
12.99 +1.75x <=35
Subtracting both sides by 12.99, we get
12.99-12.99 +1.75x <=35-12.99
1.75x <= 22.01.
Dviding both sides by 1.75
1.75x/1.75 <= 22.01/1.75
x< = 12.5771..
We got value of x less than or equal to 12.5771.... Number of rides could be a whole number.
Therefore, 12 are the maximum number of rides you can enjoy at the hot summer fair.
The answer is A! The simplified equation would be 6x-6+8 and then it simplifies to 6x+2!
Answer:
The corresponding lengths, from the point of rotation, between the pre-image and the image are preserved.
Step-by-step explanation:
As pre image is ΔQRS and image is ΔQ'R'S' . it shows that triangle is rorated at 360°. So that image is exactly same as pre image .
It would be 7c+9t (i’m pretty sure, i’m not 100% sure but seems like it’s the right answer since it’s $7 to wash a c(car) and $9 to wash a T(truck)
