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MariettaO [177]
3 years ago
11

The sum of the interior angles of a polygon measure 2880°. what is the name of the polygon?

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
8 0
The name of the polygon is an Octdecagon, or in other words, a 18-sided polygon. You find the total angles of a polygon by the formula (n - 2) * 180. What I did in this case to find the number of sides, was that I divided 2,880 by 180. My quotient was 16. Then, I added 2 in order to get 18. I did the reverse by doing (18 - 2) * 180 to check my answer, and it equaled 2,880.
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Gala2k [10]

Answer:

C is (-18, 24)

Scale factor 1 1/3

A is (9, - 4 1/2)  *4 1/2 is also 4.5

Step-by-step explanation:

When we take a look at image B (-24, -12) and pre image B (-18, -9),

we can work out the scale factor by

(-24/-18) and (-12/-9) both equal 4/3

So using the scale factor to go from the pre image to the image,

We can find C coordinate by multiplying pre image C by the scale factor.

C is (-13.5 x 4/3) and (18 x 4/3)

C is (-18, 24)

The scale factor is 4/3, which is the mixed numeral of 1 1/3.

To find the pre image of point A we divide the image by the scale factor

A is (12/(4/3)) and (-6/(4/3))

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Hope this helps,

Cate

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4 years ago
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15 more than half a number is 9
avanturin [10]
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4 0
3 years ago
Total profit P is defined as total revenue R minus total cost​ C, and is given by the function P(x)=R(x)−C(x). Find the total pr
satela [25.4K]

Given:

The revenue function is

R(x)=126.98x-0.5x^2

The cost function is

C(x)=3809.40+0.7x^2

To find:

The profit function.

Solution:

We know that, the total profit P is defined as total revenue R minus total cost​ C.

So, the profit function is

P(x)=R(x)-C(x)

P(x)=126.98x-0.5x^2-(3809.40+0.7x^2)

P(x)=126.98x-0.5x^2-3809.40-0.7x^2

P(x)=-3682.42-1.2x^2

Therefore, the profit function is P(x)=-3682.42-1.2x^2.

5 0
3 years ago
How many 1/4 inch cubes does it take to fill a box with width 3 1/4 inches, length 4 1/2 inches, and height 2 3/4 inches?
Anastaziya [24]
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3 years ago
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A concert hall has 8,000 seats and two categories of ticket prices, $29 and $34. Assume that all seats in each category can be s
Greeley [361]

Using a system of equations, it is found that:

  • For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.
  • For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.
  • For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

--------------------

The variables of the system are:

  • x, which is the number of $29 tickets sold.
  • y, which is the number of $34 tickets sold.

Total of 8,000 seats, all can be sold, thus:

x + y = 8000 \rightarrow x = 8000 - y

--------------------

For a profit of $255,000, we have that:

29x + 34y = 255000

29(8000 - y) + 34y = 255000

5y = 23000

y = \frac{23000}{5}

y = 4600

x = 8000 - 4600 = 3400

For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.

--------------------

For a profit of $271,000, we have that:

29x + 34y = 271000

29(8000 - y) + 34y = 271000

5y = 39000

y = \frac{39000}{5}

y = 7800

x = 8000 - 7800= 200

For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.

--------------------

For a profit of $235,000, we have that:

29x + 34y = 235000

29(8000 - y) + 34y = 235000

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y = \frac{3000}{5}

y = 600

x = 8000 - 600 = 7400

For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

A similar problem is given at brainly.com/question/22826010

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