The equation of line parallel to
and containing the point(-10,-3) is 
Step-by-step explanation:
We need to write the equation parallel to and containing the point(-10,-3)
The standard form of point slope equation is:
where m is slope and b is y-intercept
Comparing the given equation with standard form the slope is m= -1/5
Since the lines are parallel the slope of new line is m = -1/5
Now finding b (y-intercept)
Using slope m=-1/5 and point (-10,-3)
So, b= -5 and slope = -1/5 the equation of new line is:
So, The equation of line parallel to and containing the point(-10,-3) is
Keywords: Point Slope form
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Answer:
i think it's n/2 may be even and 3n+1 is odd. They succumb to 3n if that helps.
Step-by-step explanation:
hope it helps, have a good day/night
<h3>Given Equation:</h3>
x = 7 + 3y
or, x - 3y - 7 = 0 ........ (i)
5x + 6y = 14
or, 5x + 6y - 14 = 0 .........(ii)
<h3>To Find:</h3>
The value of x and y.
<h3>Solution:</h3>
By dividing eq. ii by 2, we get
5/2x + 3y - 7 = 0 ........ (iii)
By adding eq. i and eq. iii, we get
15/2x = 0
or, <u>x = 0</u> ........(iv)
By putting eq.(iv) in eq. (i), we get
0 - 3y - 7 = 0
or, -3y = 7
or, <u>y = </u><u>-</u><u>7/</u><u>3</u>
<h2>Answer: ( 0, -7/3 )</h2>
The value of x and y is 0 and -7/3 respectively.
