Answer:
y=-3/16(x-8)^2+12
Step-by-step explanation:
Refer to the vertex form equation for a parabola:
y=a(x-h)^2+k where (h,k) is the vertex.
Therefore, we have y=a(x-8)^2+12 as our equation so far. If we plug in (16,0) we can find a:
0=a(16-8)^2+12
0=64a+12
-12=64a
-12/64=a
-3/16=a
Therefore, your final equation is y=-3/16(x-8)^2+12
1. You have the following information:
- <span> The square has the same area as a rectangle.
- The dimensions of the rectangle are: 14 mm long and 16 mm wide.
2. You must use the formula for calculate the area of a square, which is shown below:
A=S</span>²
"A" is the area of the square.<span>
"S" is the lenght of the side of the square. (It is important to remember that the sides of a squre have equals lenghts.
3. The square and the rectangle have the same area. Therefore:
Arectangle=(14 mm)(16 mm)
Arectangle=224 mm</span>²
<span>
A=224 mm</span>²
<span>
4. Now, you must substitute the value A=224 mm</span>² into the formula A=S² and clear "S":
<span>
A=S</span>²
<span> S=</span>√A
<span> S=</span>√(224 mm²)
<span> S=15 mm
The answer is: 15 mm
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