Step-by-step explanation:

A= 3.14 × 22^2
A = 1519.78 m^2
C,
{(-1, -3),(0,-1),(1,1),(2,3),(3,5)}
Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
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Answer:
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Answer:
The expression used to find the nth term of each sequence 9, 17, 25, 33 will be:
Step-by-step explanation:
Given the sequence
9, 17, 25, 33
a₁ = 9
<em>Determining the common difference</em>
d = 17-9 = 8
d = 25-17 = 8
d = 33-25 = 8
As the common difference between the adjacent terms is same and equal to
d = 8
Therefore, the given sequence is an Arithmetic sequence.
An arithmetic sequence has a constant difference 'd' and is defined by

substituting a₁ = 9, d = 8 in the equation


Therefore, the expression used to find the nth term of each sequence 9, 17, 25, 33 will be: