The answer is C
it's easier if you graph it
we know that the x of the unknown vertice is 4, because this is a rectangle and that vertices has to be on the same x line as the point below.
y of the unknown vertice has to be 1 because the vertice to the left needs to be on the same y line as the unknown vertice
Answer:
8t(t - 5)^2
Step-by-step explanation:
I would immediately rearrange these terms in descending order by powers of t:
8t^3 - 80t^2 + 200t
Then I'd factor out 8t:
8t(t^2 - 10 t + 25).
Finally, I'd factor the quadratic t^2 - 10 t + 25:
(t - 5)^2
and so 200t+8t^3-80t^2 in factored form is 8t(t - 5)^2.
(x - h)^2 + (y - k)^2 = r^2
x^2 + (y + 6)^2 = 100
we can rewrite this as
(x-0)^2 + (y - -6)^2 = 10^2
the center is (0,-6) and the radius is 10