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3 years ago

F p, q, and r are rational numbers, which of the following equations is/are true?

Mathematics

1 answer:

Kamila [148]3 years ago

7 0

Answer:

I and II are true

(would really appreciate the brainliest)

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From 1990 to 2000, the consumer price index (CPI) increased from

lutik1710 [3]

Answer:

1.09 $

Step-by-step explanation:

From 1990 to 2000 ( 10 years ) the consumer price index increased from

130.7 to 172.2 then

172,2 - 130.7 = 41.5 % was the net increase, if peaches suffered similar increase then we will look for 41.5 % of peaches price ( 1990)

0,77 ⇒ 100

x ?? ⇒ 41.5

x = 0,77* 41,5 / 100

x = 0,3196

Then price of a pound peaches in 2000 will be

0,77 + 0,32 = 1.09 $

6 0

3 years ago

Write a decimal equation that has a product of 3.15

Vaselesa [24]

<span>you could have 3.15=100 times 0.0315, 10 times 0.315.</span>

4 0

4 years ago

A local theater charges $26 each adult ticket and $17 for each student ticket. For one show, the theater took in $988 from adult

Wewaii [24]

81 people attended !!!!

4 0

3 years ago

Which of the polynomial equations cannot be solved using the quadratic formula?

xxMikexx [17]

Answer:

The polynomial equation that cannot be solved using the quadratic formula: Option2: $x^2-2x^3-5=0$

Step-by-step explanation:

First of all we have to learn what a quadratic polynomial is.

A polynomial or equation of degree 2 is called a quadratic equation. Quadratic formula is used to solve quadratic equations.

The quadratic equation is of the form:

$ax^2+bx+c = 0$

From the given options, only option 2 doesn't have degree 2 so it is not a quadratic polynomial.

Hence,

The polynomial equation that cannot be solved using the quadratic formula: Option2: $x^2-2x^3-5=0$

8 0

3 years ago

A population of protozoa develops with a constant relative growth rate of 0.4964 per member per day. On day zero the population

vodka [1.7K]

Answer:

The population size after eight days is about 265

Step-by-step explanation:

This is an example of an exponential growth model. A quantity <em>y</em> that grows or decays at a rate proportional to its size fits in an equation of the form

$\frac{dy}{dt}=ky$

where k is a positive constant. Its solutions have the form

$y=y_{0}e^{kt}$ ,

where $y_{0} =y(0)$ is the initial value of y.

The population size can be calculated by using the below formula:

$P(t)=P(0)e^{kt}$ where $P(0)$ is the population on day zero.

Let t be the time in days,

We know from the information given that:

k = 0.4964 per member per day and

The day zero (t = 0) the population size is 5 (P(0) = 5)

To find the population size after eight days

Substitute P(0) = 5, k=0.4964 in $P(t)=P(0)e^{kt}$

Then

$P(t)=5e^{0.4964\cdot t}$

Now we calculate P(t) when t = 8 days

$P(8) = 5e^{0.4964\cdot 8}\\P(8) = 5e^{3.9712}\\e^{3.9712}=53.04815\dots \\P(8) = 5 \cdot 53.04815\dots\\P(8) = 265.24075\dots \approx 265$

Therefore the population size after eight days is about 265

8 0

3 years ago