Answer:
(4/3, 7/3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Terms/Coefficients
- Coordinates (x, y)
- Solving systems of equations of using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
7x - y = 7
x + 2y = 6
<u>Step 2: Rewrite Systems</u>
Equation: x + 2y = 6
- [Subtraction Property of Equality] Subtract 2y on both sides: x = 6 - 2y
<u>Step 3: Redefine Systems</u>
7x - y = 7
x = 6 - 2y
<u>Step 4: Solve for </u><em><u>y</u></em>
<em>Substitution</em>
- Substitute in <em>x</em>: 7(6 - 2y) - y = 7
- Distribute 7: 42 - 14y - y = 7
- Combine like terms: 42 - 15y = 7
- [Subtraction Property of Equality] Subtract 42 on both sides: -15y = -35
- [Division Property of Equality] Divide -15 on both sides: y = 7/3
<u>Step 5: Solve for </u><em><u>x</u></em>
- Define original equation: x + 2y = 6
- Substitute in <em>y</em>: x + 2(7/3) = 6
- Multiply: x + 14/3 = 6
- [Subtraction Property of Equality] Subtract 14/3 on both sides: x = 4/3
A line is a set of points that has no beginning and no end.
The property of soils which depends on the size of particles is Texture.
<h3>Properties of Soil</h3>
The properties of Soil include colour, odor, temperature, and texture as measured by porosity, mouldability and a host of other texture effects.
- It is evident that the texture of soil is dependent on the size of the particles as it affects how packed the particles of the soil is.
Read more on properties of soil;
brainly.com/question/26462165
Answer:
14.13 in³
Step-by-step explanation:
Volume of a ball (sphere) is:
V = ⁴/₃ π r³
Circumference of a ball (circle) is:
C = 2π r
Use the circumference to find the radius.
9.42 in = 2π r
r = 1.50 in
Use the radius to find the volume:
V = ⁴/₃ π (1.50 in)³
V = 14.13 in³
V(x) = (2x - 3)/(5x + 4) The domain is all Real numbers except x = -4/5, because if x = -4/5 the denominator would be zero and you cannot divide by zero.{x | x ∈ R, x ≠ -4/5} w(x) = (5x + 4)/(2x - 3)similarly, x ≠ 3/2so, {x| x ∈ R, x ≠ 3/2}
