Answer:
The area of rhombus PQRS is 120 m.
Step-by-step explanation:
Consider the rhombus PQRS.
All the sides of a rhombus are equal.
Hence, PQ = QR = RS = SP = 13 m
The diagonals PR and QS bisect each other.
Let the point at of intersection of the two diagonals be denoted by <em>X</em>.
Consider the triangle QXR.
QR = 13 m
XR = 12 m
The triangle QXR is a right angled triangle.
Using the Pythagorean theorem compute the length of QX as follows:
QR² = XR² + QX²
QX² = QR² - XR²
= 13² - 12²
= 25
QX = √25
= 5 m
The measure of the two diagonals are:
PR = 2 × XR = 2 × 12 = 24 m
QS = 2 × QX = 2 × 5 = 10 m
The area of a rhombus is:
Compute the area of rhombus PQRS as follows:
Thus, the area of rhombus PQRS is 120 m.
19. 4/6 or 2/3 (lowest term) or 2:3 in ratio
20. 2/3 or 2:3 in ratio
21. 5/12 or 5:12 in ratio
22. 14
To get geometric mean, multiply the numbers then get the square root of the product (if there are two numbers), cube root (if there are three numbers), and so on. In this case, 7*28 = 196; √196 = 14
23. 10 ft : 2.5 ft.
Convert the values so that it will be similar. In this case, 30 inches is converted to ft.
24. 24 is the Perimeter of ABCDE.
ABCDE and FGHJK are similar shapes. Similar shapes have proportional measurements.
Now compute for the sides of ABCDE.
AB = 4; BC = ?; CD = ?; DE = ?; EA = ?
AB + BC + CD + DE + EA
4 + 4 + 5 + 6 + 5 = 24
Find BC:
AB/BC = FG/GH
4/BC = 8/8
8BC = 32
BC = 4
Find CD:
BC/CD = GH/HJ
4/CD = 8/10
8CD = 40
CD = 5
Find DE:
CD/DE = HJ/JK
5/DE = 10/12
10DE = 60
DE = 6
Find EA
DE/EA = JK/KF
6/EA = 12/10
12EA = 60
EA = 5
Answer: -23
Step-by-step explanation: -23 + 5 = -18
Answer:
243 feet
Step-by-step explanation:
Multiply 10 by 6 to make an hour and also multiply 40 1/2 or 40.5 by 6
More details would be great
