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Troyanec [42]
3 years ago
12

As a computer programmer, you have to define the movements of a battleship across a virtual grid . Will you program the transfor

mation from the original position ( figure 1 ) to the final position ( figure 2 ) as a translation , reflection , or rotation?
Mathematics
1 answer:
n200080 [17]3 years ago
3 0
I took this test the other day I put figure 2 and I got it right
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4. If DF = 9x - 39, find EF.<br><br> Help I’m so confused!!!!
topjm [15]

Answer:

EF =58

Step-by-step explanation:

from the illustration,

EF =DF - DE

<em>give</em><em>n</em><em> </em><em>that</em><em> </em><em>DF</em><em> </em><em>=</em><em>9</em><em>x</em><em>-</em><em>3</em><em>9</em><em> </em><em>,</em><em> </em><em>DE</em><em> </em><em>=</em><em>4</em><em>7</em><em> </em><em>EF</em><em>=</em><em>3</em><em>x</em><em> </em><em>+</em><em>1</em><em>0</em>

<em>sub</em><em>stitute</em><em> </em><em>them</em><em> </em><em>into</em><em> </em><em>the</em><em> </em><em>formu</em><em>la</em><em>,</em>

<em> </em><em> </em>

<em>3</em><em>x</em><em> </em><em>+</em><em>1</em><em>0</em><em>=</em><em>9</em><em>x</em><em>-</em><em>3</em><em>9</em><em> </em><em>-</em><em> </em><em>4</em><em>7</em>

<em>sol</em><em>ving</em><em> </em><em>for</em><em> </em><em>x</em>

<em>3</em><em>x</em><em> </em><em>+</em><em>1</em><em>0</em><em> </em><em>=</em><em>9</em><em>x</em><em> </em><em>-</em><em>8</em><em>6</em>

<em>grou</em><em>ping</em><em> like</em><em> </em><em>ter</em><em>ms</em>

<em>3</em><em>x</em><em> </em><em>-</em><em> </em><em>9x</em><em> </em><em>=</em><em>-</em><em>8</em><em>6</em><em> </em><em>-</em><em>1</em><em>0</em>

<em>-6x</em><em>=</em><em>-</em><em>9</em><em>6</em>

<em>div</em><em>iding</em><em> </em><em>throu</em><em>gh</em><em> </em><em>by</em><em> </em><em>-</em><em>6</em>

<em>\frac{ - 6x}{ - 6}  =  \frac{ - 96}{ - 6}</em>

<em>x  =  \frac{96}{6}</em>

<em>x = 16</em>

<em>but</em><em> </em><em>EF</em><em>=</em><em>3</em><em>x</em><em>+</em><em>1</em><em>0</em>

substitute x=16 into it to get the EF

EF= 3(16)+10

EF=48+10

EF=58

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3 years ago
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How are the real solutions of a quadratic equation related to the graph of the quadratic function?
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The solutions you get when you solve the formula are the corresponding y coordinates to your x value. So say a point on your graph is (2,3). The first number is x and the second is y. (x,y). The number you plug into your function is x,or in this case: 2. The solution to the equation when the x value is plugged in is y, or 3. Therefore, giving you a point on your graph.
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I was wondering if someone could help me out, I’m not to sure how to answer this, I thought it was just adding the exponents sin
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Answer:

(1/2)^14

Step-by-step explanation:

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1,40

Step-by-step explanation:

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