Question

What is the surface area of the cylinder in term of pi? Radius of 11 and height of 23

Answer 1

Answer:2349.91

Step-by-step explanation:

A=2πrh+2πr2=2·π·11·23+2·π·112≈2349.9113

Answer 2

Answer:

The surface area of the cylinder is $748\pi$.

Step-by-step explanation:

Given : Radius of the cylinder is 11 unit and height of the cylinder is 23 unit.

To find : What is the surface area of the cylinder in term of pi?

Solution :  

The formula of surface area of cylinder is

$A=2 \pi r^2+2\pi rh$

Where, r is the radius of the cylinder r=11 unit.

h is the height of the cylinder h=23 unit.

Substitute the value in the formula,

$A=2 \pi r^2+2\pi rh$

$A=2\pi(r^2+rh)$

$A=2\pi(11^2+11(23))$

$A=2\pi(121+253)$

$A=2\pi(374)$

$A=748\pi$

Therefore, The surface area of the cylinder is $748\pi$.