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Hoochie [10]
2 years ago
14

Determine the area of the given region under the curve (1/x^4) [1,2]

Mathematics
1 answer:
Nikolay [14]2 years ago
6 0

Answer:

\displaystyle \frac{7}{24}

General Formulas and Concepts:

<u>Algebra I</u>

  • Exponential Rule [Rewrite]: \displaystyle b^{-m} = \frac{1}{b^m}

<u>Calculus</u>

[Area] Limits of Riemann's Sums - Integrals

Integration Rule [Reverse Power Rule]:                                                                    \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Rule [Fundamental Theorem of Calculus 1]:                                          \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle f(x) = \frac{1}{x^4} \\ \ [1, 2]<u />

<u />

<u>Step 2: Find Area</u>

  1. [Integral] Set up area:                                                                                    \displaystyle \int\limits^2_1 {\frac{1}{x^4}} \, dx
  2. [Integral] Rewrite:                                                                                            \displaystyle \int\limits^2_1 {x^{-4}} \, dx
  3. [Integral] Reverse Power Rule:                                                                      \displaystyle \frac{-1}{3x^3} \bigg| \limits^2_1
  4. [Area] Fundamental Theorem of Calculus:                                                   \displaystyle \frac{7}{24}

Topic: Calculus

Unit: Basic Integration/Riemann Sums

Book: College Calculus 10e

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Given:
Cone shape: radius = 24 cm ; height = 6cm
Cylinder: radius = 16cm

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Volume of a cone = π r² h/3 = 3.14 * 24² * 6/3 = 3.14 * 576 * 2 = 3,617.28

Volume of a cylinder = π r² h
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