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alexandr1967 [171]

2 years ago

10

What is 97,079 rounded to the nearest ten thousand

2 answers:

Kazeer [188]2 years ago

8 0

Answer:

97000

Step-by-step explanation:

look the the left of the column asked for. if it's 0-4 it stays the same but if it's 5-9 it goes up on. e.g if the number was 97508 it would go to 98000

Levart [38]2 years ago

7 0

Answer:

Hey mate....

Step-by-step explanation:

This is ur answer.....

<h3>97,079 rounded to the nearest ten thousand...</h3>

<em>Step 1 : Identify the next smallest place value 7 in 97,079. </em>

<em>Step 2 : We can the digit greater than five , so it would be rounded up.</em>

<em> Step 3 : The ten thousand digit 9 become increased by 1 and Every digit. </em>

<em>Step 4 : Number become 100,000. Answer: Therefore, Number would be 100,000 </em>

Hope it helps!

Brainliest pls!

Follow me! ;)

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2 years ago

The midpoint of y and 31 is -5. what is y

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4 0

3 years ago

Prove that the segments joining the midpoint of consecutive sides of an isosceles trapezoid form a rhombus.

sergiy2304 [10]

Answer:

See explanation

Step-by-step explanation:

a) To prove that DEFG is a rhombus, it is sufficient to prove that:

All the sides of the rhombus are congruent: $|DG|\cong |GF| \cong |EF| \cong |DE|$
The diagonals are perpendicular

Using the distance formula; $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$|DG|=\sqrt{(0-(-a-b))^2+(0-c)^2}$

$\implies |DG|=\sqrt{a^2+b^2+c^2+2ab}$

$|GF|=\sqrt{((a+b)-0)^2+(c-0)^2}$

$\implies |GF|=\sqrt{a^2+b^2+c^2+2ab}$

$|EF|=\sqrt{((a+b)-0)^2+(c-2c)^2}$

$\implies |EF|=\sqrt{a^2+b^2+c^2+2ab}$

$|DE|=\sqrt{(0-(-a-b))^2+(2c-c)^2}$

$\implies |DE|=\sqrt{a^2+b^2+c^2+2ab}$

Using the slope formula; $m=\frac{y_2-y_1}{x_2-x_1}$

The slope of EG is $m_{EG}=\frac{2c-0}{0-0}$

$\implies m_{EG}=\frac{2c}{0}$

The slope of EG is undefined hence it is a vertical line.

The slope of DF is $m_{DF}=\frac{c-c}{a+b-(-a-b)}$

$\implies m_{DF}=\frac{0}{2a+2b)}=0$

The slope of DF is zero, hence it is a horizontal line.

A horizontal line meets a vertical line at 90 degrees.

Conclusion:

Since $|DG|\cong |GF| \cong |EF| \cong |DE|$ and $DF \perp FG$ , DEFG is a rhombus

b) Using the slope formula:

The slope of DE is $m_{DE}=\frac{2c-c}{0-(-a-b)}$

$m_{DE}=\frac{c}{a+b)}$

The slope of FG is $m_{FG}=\frac{c-0}{a+b-0}$

$\implies m_{FG}=\frac{c}{a+b}$

5 0

3 years ago