Answer:
percent (%) of ancient prehistoric thinner than 3 is 0.0013
Step-by-step explanation:
Given data
mean = 5.1 millimeters (mm)
standard deviation = 0.7 mm
to find out
percent (%) of ancient prehistoric thinner than 3
solution
we have given mean and SD
so Z will be = x -mean / SD
Z = ( x - 5.1 ) / 0.7
so P( x < 3 ) = P ( (x - 5.1 ) / 0.7 < ( 3 - 5.1 ) / 0.7 )
P( Z = ( 3 - 5.1 ) / 1.5 )
P( Z = -3 ) = 0.0013
percent (%) of ancient prehistoric thinner than 3 is 0.0013
3. straight line
8.obtuse
12.acute
The distributive property states that:
a(b+c)=ab+bc.
or more generally: a(b+c+d)=ab+av+ad.
This is a very useful tool to perform multiplication.
For example, if we want to multiply 7 by 234, we can proceed as follows:
7*234=7(200+30+4)=7*200+7*30+7*4=1400+210+28=1610+28=1638
back to our problem,
4 * 24 = 4(20+4)=4*20+4*4=80+16=96 ($)
So, instead of multiplying 4 by 24, we multiplied 4 by 20 and 4, which is easier, and then added these together.
Answer:
4 * 24 = 4(20+4) [=4*20+4*4=80+16=96 ($)]
The answer is 1.75 dollars for one
Please Give Me Brainliest Answer :D
If each pack of trail mixes is targeted to weigh 9.25 oz and must be within 0.23 oz of the target in order to be accepted, then rejected masses x, are those which weighs less than 9.02 oz or greater than 9.48 oz.
