Find the area of a circle with a circumference of 31.5 units

Mathematics

1 answer:

Westkost [7]3 years ago

6 0

Answer:

79 units²

Step-by-step explanation:

The area of a circle is found by using the formula A = π x r². Since we are not given the radius we can use the formula r = C / (2π). Substituting in the given values, we get r = 31.5/(2π). 2 times pi is 6.283185307. 31.5 divided by this will get you 5.013380707. Now, put that value in for r in the area equation. A = π x 5.013380707². Pi times 5.013380707² equals 78.96074613. This can be rounded to 79. (Or 80 if you need to the nearest whole number.)

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Answer:

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kolezko [41]

We are given the following quadratic equation

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The vertex is the maximum/minimum point of the quadratic equation.

The x-coordinate of the vertex is given by

$h=-\frac{b}{2a}$

Comparing the given equation with the general form of the quadratic equation, the coefficients are

a = 2

b = 7

c = -10

$h=-\frac{b}{2a}=-\frac{7}{2(2)}=-\frac{7}{4}=-1.75$

The y-coordinate of the vertex is given by

$\begin{gathered} f(x)=2x^2+7x-10 \\ f(-1.75)=2(-1.75)^2+7(-1.75)-10 \\ f(-1.75)=2(3.0625)^{}-12.25-10 \\ f(-1.75)=6.125^{}-12.25-10 \\ f\mleft(-1.75\mright)=-16.13 \end{gathered}$

This means that we have a minimum point.

Therefore, the minimum point of the given quadratic equation is