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Sergio039 [100]
3 years ago
8

The hour hand of a clock moves from 6

Mathematics
2 answers:
svp [43]3 years ago
5 0
90 degrees. Looking at a clock, 12 o'clock going all the way around and back is a 360 degree spin. So 12, 3, 6, and 9 are all 1/4 of a 360 degree spin. If you divide 360 by, you would get a 90 degree turn for each of those numbers mentioned above.
wlad13 [49]3 years ago
4 0
Angles around a point adds up to 360°. the clock is divided into 12 parts to read time, so first we should divide 360° by 12.
360°÷12=30,
difference between 6 and 9 is 3 so, next we have to multiply 30 by 3.
30×3=90
answer-90°
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Question is attached ​
SSSSS [86.1K]
I think the answer is A.
4 0
3 years ago
Consider the surface f (x comma y comma z )f(x,y,z)equals=negative 2 x squared plus 2 y squared minus 3 z squared plus 3 equals
trapecia [35]

Answer:

a) (8,8,-6)

b) 4x+4y+3z = -3

Step-by-step explanation:

a)

The surface is given by the equation  

f(x,y,z) = 0 where

f(x,y,z)=-2x^2+2y^2-3z^2+3

The gradient of this function is the vector

(\frac{\partial f}{\partial x},\frac{\partial f}{\partial y},\frac{\partial f}{\partial z})=(-4x,4y,-6z)

If we evaluate it in the point P = (-2,2,1) we obtain the point

(8,8,-6)

b)

The vectors with their tails at P are of the form  

(-2,2,1)-(x,y,z) = (-2-x, 2-y, 1-z)

as they must be orthogonal to the gradient, they must be orthogonal to the vector (8,8,6) so their inner product is 0

(-2-x,2-y,1-z)\cdot(8,8,6)=0\Rightarrow -16-8x+16-8y+6-6z=0\Rightarrow 4x+4y+3z=-3

and the equation of the desired plane is

4x+4y+3z = -3

3 0
4 years ago
when derek planted a tree it was 36 inches tall. the tree grew 1 1/4 inches per year the tree is now 44 3/4 inches tall. how man
mafiozo [28]
Derek would have planted the tree 7 years ago. You subtract 36 from 44.75 and get 8.75. This is how much the tree grew since he planted it. Then, you'll divide 8.75 by 1.25 (1 1/4) which tells you how many years it has been since he planted the tree. The final answer is 7 years. Hope this helps!
8 0
4 years ago
Yesterday, there were 80 problems assigned for homework. Harry did 20% of them correctly. How many problems did Harry get right?
konstantin123 [22]

Answer:

16 i think

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The half-life of uranium-238 is 4.5x10^9 years. The half-life of uranium-234 is 2.5x10^5 years. How many times greater is the ha
lara31 [8.8K]

<u>Answer:</u>

Half-life of uranium-238 18 \times 10^{3} \text { times greater } that of uranium-234

<u>Explanation:</u>

Half time of uranium-238 = 4.5\times 10^9  years

Half time of Uranium-234 = 2.5\times 10^5 years

To find how much times greater the half life of uranium-238 is from uranium-234

= \frac{\text { Half life of Uranium-238 }}{\text { Half time of Uranium - 234 }}

=\frac{4.5 \times 10^{9}}{2.5 \times 10^{5}}

=18 \times 10^{3} \text { times greater }

Hence Uranium-238 is  18 \times 10^{3} \text { times greater } than Uranium-234

4 0
3 years ago
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