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2 years ago

Are the ratios 25/45 and 15/27 proportional? Explain.

1 answer:

6 0

Write them out as a fraction then reduce them. If theyre the same then its proportional.

25/45 can be cancelled down to 5/9

15/27 can be cancelled down to 3/9

So no theyre not.

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AB and BC are tangents of circle P. What is the value of x?

koban [17]

There are several information's already given in the question. It is very important to look at the attached diagram very closely. The angle given in the question is 73 degrees.
Then
x = 180 - 73
= 107 degrees
I hope that this is the answer that you were looking for and the answer has actually come to your desired help.

7 0

2 years ago

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Which graph shows the result of dilating this figure by a factor of 3 about the origin?

SVETLANKA909090 [29]

Do you have a picture that shows the graphs

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3 years ago

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A train 100 m long crosses a pole in 5 seconds.Find the speed of the train in kilometre per hour.

In-s [12.5K]

Answer:

$\sf72 km/h$

Step-by-step explanation:

Distance covered by the train in crossing the pole = 100 m.

$\sf Time \: taken=5 \: seconds$

$\sf \: Speed \: of \: the \: train = \frac{Distance }{Time}$

$\sf = \frac{100}{5} \: m/s$

$\sf \: = 20 \: m/s$

$\sf \: = 20 \times \frac{18}{5} \: km/h$

$\sf = 72 \: km/h$

Hence, the speed of the train is 72 km/h

6 0

2 years ago

How many solutions ? ( 1 solution , no solution , infinite solutions ) I WILL MAKE U BRAINLIST NEED ASAP

tangare [24]

Answer:

#4 = ∞

#5= no solution

#6= no solution

Step-by-step explanation:

GOOD LUCK!!!!

4 0

2 years ago

PLSS HELP ILL GIVE YOU BRAINLIEST!!

uysha [10]

Answer:

Step-by-step explanation:

Q1)

Use Phythogoras theorem:

$(AC)^2=(BC)^2+(AB)^2\\BC^2=AC^2-AB^2\\BC^2=6^2-4^2\\BC^2=36-16\\BC^2=20\\\\Apply\ square\ on\ both\ sides\\\\\sqrt{BC^2}=\sqrt{20} \\BC=\sqrt{20} \\BC=\sqrt{10(2)} \\BC=\sqrt{5(2)(2)} \\BC=2\sqrt{5}$

Q2)

Apply phythogoras theorem:

$CD^2=CE^2+DE^2\\CD^2=7^2+9^2\\CD^2=49+81\\CD^2=130\\\\Apply\ square\ root\ on\ both\ sides\\\\\\sqrt{CD^2} = \sqrt{130} \\\\CD=\sqrt{130} \\\\CD=11.4$

Q3)

Apply phythogoras theorem again:

$BC^2=BD^2+CD^2\\BC^2=7^2+13^2\\BC^2=49+169\\BC^2=218\\\\Apply\ square\ root\ on\ both\ sides\\\\\\sqrt{BC^2} =\sqrt{218} \\\\BC=\sqrt{218} \\\\BC=14.76$

I have an attached an image for Question 2 for better understanding the length of DE in question equals 15 - 6 = 9

4 0

2 years ago