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JulijaS [17]
3 years ago
8

A hyena runs 2 kilometers for every 25 kilometer a mouse runs. Select from the drop-down menu to correctly complete the statemen

t. The hyena runs kilometers for every kilometer the mouse runs.
Mathematics
1 answer:
xxMikexx [17]3 years ago
6 0

Given that a hyena runs 2 kilometers for every 25 kilometer a mouse runs.

Now we need to select from the drop-down menu to correctly complete the statement. Where given statement is "The hyena runs kilometers for every kilometer the mouse runs."

"every kilometer" indicates we need to find number of kilometers for hyena when mouse runs 1 kilometer.

To find that we will divide number of kilometers of hyena by number of kilometers of mouse that is divide 2 by 25.

2/25=0.08

Hence final answer will be :

"The hyena runs 0.08  kilometers for every kilometer the mouse runs."

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I really need help with this! Thank you!!
photoshop1234 [79]
<h3>Answer:</h3>
  1. x = 13; NP = 2 18/23 ≈ 2.8; NL = 5 5/23 ≈ 5.2
  2. D. x = 17, y = 5
<h3>Step-by-step explanation:</h3>

1. In order for this problem to be workable, we need to assume PQ ║ ML. Then ΔPNQ ~ ΔLNM and ∠L = ∠P = 60°.

... ∠L = 60°

... (3x+21)° = 60°

... 3x = 39 . . . . . . . divide by °, subtract 21

... x = 13 . . . . . . . . .divide by 3

The side lengths of similar triangles are proportional, so we have ...

... (3.2 cm)/y = (6 cm)/(8-y)

Multiplying by the product of the denominators, and dividing by (cm), we have ...

... 3.2(8 -y) = 6y

... 3.2×8 = 9.2y . . . . . add 3.2y

... y = 3.2×8/9.2 = 64/23 = 2 18/23 ≈ 2.78 = NP

Then ...

... 8-y = NL ≈ 5.22

In summary: x = 13; NP ≈ 2.8; NL ≈ 5.2

_____

2. If we assume figures ABCD and PSRQ are similar, we can find the values of the variables. We assume ∠C ≅ ∠R, so ...

... 4x +27° = 95°

... 4x = 68° . . . . . subtract 27°

... x = 17° . . . . . . . divide by 4

___

AB/AD = PS/PQ . . . . . corresponding sides of similar figures are proportional

... 4y/(3y-5) = 10/5 . . . . . units of ft cancel

... 5×4y = 10(3y -5) . . . . . multiply by 5(3y-5)

... 20y = 30y -50 . . . . . . simplify

... 50 = 10y . . . . . . . . . . . add 50-20y

... 5 = y . . . . . . . . . . . . . . divide by 10

Using this value of y, we have ...

AB = 4y ft = 20 ft; AD = (3y-5) ft = 10 ft. Both these values are double the corresponding lengths on PSRQ.

In summary, x = 17°, y = 5. . . . . . (note that the ° symbol is appropriate for x)

_____

You should have your teacher show you how to work these problems <em>using only the given information</em>.

In the second problem, you cannot start with the assumption that the figures are similar, as that is what you're being asked to prove. Please note, too, that two sides and one angle of a quadrilateral are insufficient to show similarity.

7 0
3 years ago
Wats 3000000000000*30000000000000
Olegator [25]

Answer:

9E+25

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Who does e.d.e.n.u.i.t.y and needs help catching up?/ I'm free to help... only up to 8th grade though...
Mekhanik [1.2K]

Answer:

we might be starting it again soon

Step-by-step explanation:

Im in 7th and I might need help!!

4 0
2 years ago
decide if 30x-12 could be the result of using the distributive property. If it is, possible combonation of factors whose product
sergij07 [2.7K]

Answer:

89

Step-by-step explanation:

4 0
3 years ago
3. Is XY Tangent to circle Z?<br> Y<br> 12 X<br> (20<br> Z<br> 18
Ratling [72]

Answer:

XY is a tangent

Step-by-step explanation:

Given

XY = 12

WY = 20

WZ = 8

Required

Is XY a tangent?

XY is a tangent if:

WY^2 = XY^2 + WX^2

Because XY should make a right angle at point X with the circle

Where

WX = 2 * WZ

So, we have:

WY^2 = XY^2 + WX^2

WY^2 = XY^2 + (2*WZ)^2

WY^2 = XY^2 + (2WZ)^2

WY^2 = XY^2 + 4WZ^2

This gives:

20^2 = 12^2 + 4*8^2

400 = 144 + 256

400 = 400

<em>Yes, XY is a tangent</em>

4 0
2 years ago
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