.6k+.9=1.6
.6k=.7
k=7/6= 1 1/6
k= 1 1/6
Hope this helps.
Answer:
i believe the answer is D
A series of numbers called an arithmetic progression or arithmetic sequence has a constant difference between the terms.
An arithmetic progression with a common difference of 2 is found, for instance, in the numbers 5, 7, 9, 11, 13, and 15. Given that each term has a common difference, this is an arithmetic sequence.
In this instance, the result is obtained by adding 6 6 to the prior term in the sequence.
What is the arithmetic progression formula?
a {n}=a {1}+(n-1) The nth term in the series is d a n.
The first term in the sequence is a 1.
d is the common distinction between the terms.
To learn more about Arithmetic progression refer to:
brainly.com/question/24191546
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Answer:
Multiplying the variables and numbers in the parentheses by the number next to them.
Step-by-step explanation:
Answer:
0.94$
Step-by-step explanation: