Answer:
The correct answer is - 0.72 pg.
Explanation:
A we know that, genetic material present in one primary spermatocyte divides in between four sperm cells that means that each sperm cell has 25 percent of DNA or genetic material of the primary spermatocyte.
Given:
1 sperm cell = 0.18 nuclear DNA
So,
0.18*4 = DNA content of primary spermatocyte
DNA content of primary spermatocyte = 0.72 picogram
The three characteristics used to classify prokaryotes are shape, how they move, and how they get energy. Prokaryotes are unicellular or single celled organisms that lacks a membrane-bound nucleus, mitochondria, or any other membrane-bound organelles. Prokaryotes includes both bacteria and archaea and are found almost every where.
The immune system works to keep germs out of the body and destroy any that get in. The immune system is made up of a complex network of cells and organs that protect the body from infection. Lymph nodes are part of the immune system. They release lymphocytes, a certain type of white blood cell that fights infection.
Answer:
1) dominant 2) recessive 3) offspring 4) true 5) lowercase 6) uppercase 7) lowercase 8) black
Answer:
0.9342
Explanation:
The Hardy-Weinberg equation states that p² + 2pq + q² = 1,
where p is the frequency of the dominant 'normal' (n) allele and q is the frequency of the recessive 'albino' (a) allele in the population, while q² represents the frequency of the homo-zygous albino genotype (aa), p² represents the frequency of the homo-zygous normal genotype (nn) and 2pq represents the frequency of the heterozygous genotype (na).
In this case, the frequency of individuals in the population that have the genotype aa (q²) is equal to 26/6000 = 0.004333. In consequence, q is equal to √ 0.004333 = 0.0658.
Moreover, the allele frequency of the normal (n) allele p is equal to 1 - q = 1 - 0.0658 = 0.9342, so p² (nn) = (0.9342)² = 0.8727.
Finally, the frequency of the heterozygous genotype (na) is 2pq = 2 x 0.9342 x 0.0658 = 0.123.
