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gayaneshka [121]
3 years ago
10

Simplify: 4w(to the power of 9)+(-2w(to the power of 9)) enter the original expression if it cannot be simplified

Mathematics
1 answer:
igomit [66]3 years ago
6 0
4w⁹ -2w⁹
= (4-2)w⁹ . . . . . distributive property, or "collecting terms"
= 2w⁹

_____
In plain text, a caret (^) is used to identify an exponent. w⁹ = w^9. If the exponent has any arithmetic, you need parentheses around it. w^(8+1)
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Solve the two-step equation.<br><br> 14 = 31.7 – 3x<br><br> What is the solution?
shtirl [24]

Answer:

The answer is 5.9

Step-by-step explanation:

1) Subtract 31.7 from both sides.

14 - 31.7 =  - 3x

2) Simplify 14 - 31.7 to -17.7

- 17.7 =  - 3x

3) Divide both sides by -3.

\frac{ - 17.7}{ - 3}  = x

4) Simplify -17.7/-3 to 5.9

5.9 = x

5) Switch sides.

x = 5.9

Therefor, the answer is x = 5.9.

3 0
3 years ago
Solve the following equation in terms of y. Remember to use inverse operations to isolate the variable you are solving for. 2x+3
Ierofanga [76]
2x+3y=6
subtract 2x from both sides.
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divide by 3 on all sides.
y=2-2/3x
5 0
3 years ago
Hey!
noname [10]

Answer:

A. Cylinder + cone

<u>Volume is the sum of volumes:</u>

  • V = Vcon + Vcyl = 1/3πr²h₁ + πr²h₂
  • V = 1/3π*9²*12 + π*9²*120 = 31554.2 cm³

<u>Surface area of cone:</u>

  • A = A=πr(r+√(h₁²+r²)) = π*9(9 + √(9²+12²)) = 678.6 cm²

<u>Surface area of cylinder minus bases:</u>

  • A = 2πrh₂ = 2π*9*120 = 6785.8 cm²

<u>Total surface area:</u>

  • 678.6 + 6785.8 = 7464.4 cm²

-------------------------------------------------

B. Cube+ pyramid

<u>Volume:</u>

  • V = a³ + (1/3)a²h = a³ + (1/3)a²√(l²-(a/2)²)
  • V = 8³ + (1/3)8²√(10²-4²) = 707.5 cm³

<u>Surface area of pyramid:</u>

  • A = a² + 2al = 8² + 2*8*10 = 224 cm²

<u>Surface area of cube minus bases:</u>

  • A = 4a² = 4(8²) = 256 cm²

<u>Total surface area:</u>

  • A = 224 + 256 = 480 cm²
5 0
3 years ago
Determine the area of an isosceles right triangle with the equal sides each measuring 10 cm in length​
Akimi4 [234]

Check the picture below.

6 0
3 years ago
Question 27: Please help, which rigid motion could be used to show that triangle ABC is congruent to triangle BAD?
m_a_m_a [10]

Answer:

i think is B

explanation:

reflection across a vertical line

3 0
3 years ago
Read 2 more answers
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