Given end points of diameter,
(x1,y1)=(-3,-4)
(x2,y2)=(0,0)
Now,
the equation of circle is,
(x-x1)(x-x2)+(y-y1)(y-y2)=0
or, (x+3)(x-0)+(y+4)(y-0)=0
or, x^2 +3x +y^2 +4y =0
or, x^2 +y^2 +3x + 4y=0
which is in the form of x^2 +y^2 +2gx +2fy + c=0
where,
g=3/2
h=2
c=0
Now,
The roots of the equation , 2+3=m, are non real roots.
The quadratic formula's discriminant is represented by the square root symbol -4ac. If there are two solutions, one solution, or none at all, the discriminant informs us.
As of now, 2m²+3=m we need to find the kind of roots they have.
2m²+3=m
2m²-m+3=0
Here, we can derive the following values from the equation:
a = 2, b = -1, c = 3
An equation's discriminant is stated as:
D = b²-4ac
D = (-1)(-1) - 4(2)(3)
D = 1 - 24
D = -23
Discriminant can determine the kind of roots that the equation contains.
In this instance, the discriminant is below 0.
The equation's roots are complex conjugates when D < 0.
Hence the roots for the equation are non real roots.
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