What is the 23rd term of the arithmetic sequence where a1 = 8 and a9 = 48?
1 answer:
Answer:
23rd term of the arithmetic sequence is 118.
Step-by-step explanation:
In this question we have been given first term a1 = 8 and 9th term a9 = 48
we have to find the 23rd term of this arithmetic sequence.
Since in an arithmetic sequence
here a = first term
n = number of term
d = common difference
since 9th term a9 = 48
48 = 8 + (9-1)d
8d = 48 - 8 = 40
d = 40/8 = 5
Now
= 8 + (23 -1)5 = 8 + 22×5 = 8 + 110 = 118
Therefore 23rd term of the sequence is 118.
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<h2>Answer</h2>
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<h2>Explanation</h2>Let the cost of the exam hours
Let be the cost of the workshop hours
Let be the cost of the lecture hours.
We know from our problem that exam hours cost twice as much as workshop, so:
equation (1)
We also know that workshop hours cost twice as much as lecture hours, so:
equation (2)
Finally, we also know that 3hr exams 24hr workshops and 12hr lectures cost $528, so:
equation (1)
Now, lets find the value of :
Step 1. Solve for in equation (3)
equation (4)
Step 2. Replace equation (1) in equation (4) and simplify
equation (5)
Step 3. Replace equation (2) in equation (5) and solve for
Cost of lectures = $7.33 per hour