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scoundrel [369]
2 years ago
15

Elise and her dad are planning to attend the state fair. An adult ticket is $21.00. The price of an adult ticket is $10.00 more

than two thirds the price of a student ticket. Write an equation to determine how much Elise will pay for a student ticket. A)two thirdsx + 21 = 10 B)two thirdsx − 21 = 10 C)two thirdsx + 10 = 21 D)two thirdsx − 10 = 21
Mathematics
1 answer:
solong [7]2 years ago
3 0

Answer:

C. two thirds x + 10 = 21

Step-by-step explanation:

Given

Price of adult ticket = $21.00

Let x be the price of student ticket

Then

two third of the student ticket will be:

\frac{2}{3} x

The statement $10.00 more than two third of student ticket:

\frac{2}{3} x+10

As we are given in the question that the adult ticket price is $21.00 and the second explanation is th equation formed by the given statement

So, both will be equivalent

\frac{2}{3} x+10 = 21

Solving this equation for x will give us the price for the student ticket.

Hence,

C. two thirdsx + 10 = 21 is the correct answer ..

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MaRussiya [10]

Answer:

g(0) = -2

Step-by-step explanation:

Given - g(x) = -x - 2

To find - g(0)

Proof -

We have given the function ,

g(x) = -x - 2

For finding the value of g(0), we just have to put x = 0 in g(x),

We get

g(0) = -0 - 2 = -2

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3 years ago
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12345 [234]

Answer:

<em>19</em>

Step-by-step explanation:

f(x) =4x^3-8x^2+ax+b has a factor 2x-1 and

when divided by x+2, remainder is 20.

To find:Remainder when divided by (x-1)  ?

Solution:

2x-1 is a factor

2x - 1 = 0 \Rightarrow x = \frac{1}{2} when we put this value of x to the function, it will become 0.

i.e.

\Rightarrow f(\dfrac{1}{2}) =0 =4\times (\dfrac{1}2)^3-8(\dfrac{1}2)^2+\dfrac{a}{2}+b=0\\\Rightarrow \dfrac{1}{2}-2+\dfrac{a}{2}+b=0\\\Rightarrow 1-4+a+2b=0\\\Rightarrow a +2b=3 ......(1)

Remainder is 20 when f(x) is divided by x+2

i.e.

f(-2) =20

\Rightarrow f(-2) =20 =4\times (-2)^3-8(-2)^2-2a+b=20\\\Rightarrow -32-32-2a+b=20\\\Rightarrow -2a+b=84 ...... (2)

Solving (1) and (2), Multiply equation (1) by 2 and adding to (2):

5b=6+84\\\Rightarrow b = \dfrac{90}{5} = \bold{18}

By equation (1):

a+2(18) = 3\\\Rightarrow a = -33

So, the equation becomes:

f(x) =4x^3-8x^2-33x+18

\Rightarrow f(1) = 4(1) -8 (1) -33(1) +18 = \bold{19}

So, when divided by (x-1), remainder will be <em>19</em>.

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Answer:

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Step-by-step explanation:

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