Answer:
The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.
Step-by-step explanation:
According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.
Then, the mean of the distribution of sample mean is given by,

And the standard deviation of the distribution of sample mean is given by,

The information provided is:
<em>μ</em> = 144 mm
<em>σ</em> = 7 mm
<em>n</em> = 50.
Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:


*Use a <em>z</em>-table for the probability.
Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.
Answer:
Y = 6,8 X = -6,3 Z = -2, -1
Y = 9,7 X = -3,2 Z = 1,-2
Step-by-step explanation:
76.88 I just typed it in on a calculator.
This would actually be a very broad question. So, when considering these kinds of questions, one thing that we would really want to consider would be the

value in this case. We would want to find the amount, and also the terms of the expression.
So, let's suppose that the amount would be 200.
And let's say that Shauna makes 5 a week.
Then the expression would then look like


I hope this would help you in your case of the problem! :)
Answer:
B - 600 words in 12 minutes
Step-by-step explanation:
So most of this has to do with division. So let's look at answer one
320 words in 8 mins
320/8 = 40 words per minute.
600 words in 12 minutes
600/12 = 50 words per minute
350 words in 8 minutes
350/8 = 35 words per minute
And finally, 225 words in 5 minutes
225/5 = 45 words per minute. Thus, the answer is B