1 point

Chemistry

1 answer:

nignag [31]3 years ago

4 0

Answer:

9.7 atm.

Explanation:

The following data were obtained from the question:

Initial pressure (P1) = 1 atm

Initial volume (V1) = 0.725 L

Final volume (V2) = 0.075 L

Final pressure (P2) =?

The final pressure can be obtained by using the Boyle's law equation since the temperature is constant. This is illustrated below:

P1V1 = P2V2

1 x 0.725 = P2 x 0.075

Divide both side by 0.075

P2 = 0.725 / 0.075

P2 = 9.7 atm.

Therefore, the new pressure is 9.7 atm.

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A 20.0 milliliter sample of 0.200 molar K₂CO₃ solution is added to 30.0 milliliters of 0.400 molar Ba(NO₃)₂ solution. Barium car

sveticcg [70]

Answer:

0.32M

Explanation:

Step 1: Balance the reaction

K2CO3 + Ba(NO3)2 ⇔ KNO3 + BaCO3

We have a 20 mL 0.2 M K2CO3 and a 30mL 0.4M Ba(NO3)2 solution

SinceK2CO3 is the limiting reactant, there will remain Ba(NO3)2 after it's consumed and produced KNO3 + BaCO3

Step 2: Calculate concentration

To find the concentration of the barium cation we use the following equation:

Concentration = moles of the solute / volumen of the solution

[Ba2+] = (20 * 10^-3 * 0.2M + 30 * 10^-3 * 0.4M) / ( 20 + 30mL) *10^-3

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6 0

3 years ago

A buffer is prepared by adding 12.0g of ammonium chloride (NH4Cl) to 250mL of 1.00 M NH3 solution?The pH is 9.3 Write the net io

solniwko [45]

Answer:- $NH_3(aq)+H^+(aq)\rightleftharpoons NH_4^+(aq)$

Explanations:- The solution we have is a buffer solution and we know that a buffer solution resists a change in its pH if a strong acid or base is added to it.

Here, the buffer solution we have is of a weak base and it's conjugate acid. So, a strong acid(nitric acid) is added to this buffer then it reacts with the base present in the buffer so that the acid could be neutralized. This is called buffer action.

The net ionic equation is written as:

$NH_3(aq)+H^+(aq)\rightleftharpoons NH_4^+(aq)$

Note that $HNO_3$ is a strong acid and nitrate ion is the spectator ion so it is not included in the net ionic equation.