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Arlecino [84]
3 years ago
15

A sample of an ionic compound containing iron and chlorine is analyzed and found to have a molar mass of 126.8 g/mol. what is th

e charge of the iron in this compound?
Chemistry
2 answers:
kvasek [131]3 years ago
8 0

The charge of iron in the compound is 2+ and the compound is iron (II) chloride which can be represented using the chemical formula FeCl₂.

FURTHER EXPLANATION

To answer this problem, some key facts to recall are:

  1. In the chemical formula of ionic compounds, the charge of the metal becomes the subscript of the nonmetal and the charge of the nonmetal is used as the subscript of the metal.
  2. The molar mass is the mass of one mole of a substance. This is equal to the combined masses of the elements that make up the chemical compound.

In this question, the metal is iron (Fe) with its charge unknown so it can be denoted as Feˣ⁺, and the nonmetal is chlorine (Cl) which is known to have a charge of 1-. By crisscross method, the chemical formula of the compound may be written as FeClₙ.

Since the molar mass of the compound is given, the subscript n, may be determined by getting the sum of the masses of the elements that make up the substance:

molar mass of FeClₙ.=  molar mass of Fe + n{molar mass of Cl}

126.8 g/mol = 55.845 g/mol + n(35.45 g/mol)

n = 2.00

The charge, therefore, of iron in the compound is 2+. The chemical formula of iron (II) chloride is written as FeCl₂.

LEARN MORE

  1. Learn more about Empirical Formula brainly.com/question/8516072
  2. Learn more about Naming Compounds brainly.com/question/8968140
  3. Learn more about Mass Percent brainly.com/question/11042307

<em>Keywords: molar mass, compound, chemical formula, ionic compound</em>

julsineya [31]3 years ago
5 0
Answer is: <span>the charge of the iron in this compound is +2.
Atomic mass of iron is 55,8 g/mol.
Atomic mass of chlorine is 35,5 g/mol.
If compound is FeCl, molar mass would be 55,8 </span>g/mol + 35,5 g/mol = 91,3 g/mo, that is not correct.
If compound is FeCl₂, malar mass of compound would be:
55,8 g/mol + 2·35,5 g/mol = 126,8 g/mol, that is correct.
Oxaidation number of chlorine is -1.
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How many moles are in 2.5L of 1.75 M Na2CO3
Natasha_Volkova [10]

Answer:

4.4 mol.

Explanation:

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In this case, since the formula for calculating the molarity is:

M=n/V

Whereas n stands for moles and V for the volume in liters; we can solve for n as shown below when we are given the volume and the molarity:

n=V*M

Thus, we plug in the given data to obtain:

n=2.5L*1.75mol/L=4.4mol

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2 years ago
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What is the name of this alkane? two central carbons are bonded to c h 3 at each end, h below, and c h3 above the left carbon an
Kazeer [188]

The name of this alkane is with central carbons are bonded to c h 3 is 2-methylbutane.

<h3>What is alkane?</h3>

Alkanes belong to the family of  saturated hydrocarbons with carbon carbon single bond.

For the given alkane;

          CH₃    H

 CH₃ -  C   -  C - CH₃

            H      H

Thus, the name of this alkane is with central carbons are bonded to c h 3 is 2-methylbutane.

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4 0
1 year ago
A 0.1510 gram sample of a hydrocarbon produces 0.5008 gram CO2 and 0.1282 gram H2O in combustion analysis. Its
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In a combustion of a hydrocarbon compound, 2 reactions are happening per element:

C + O₂ → CO₂
2 H + 1/2 O₂ → H₂O

Thus, we can determine the amount of C and H from the masses of CO₂ and H₂O produced, respectively.

1.) Compute for the amount of C in the compound. The data you need to know are the following:
Molar mass of C = 12 g/mol
Molar mass of CO₂ = 44 g/mol
Solution:
0.5008 g CO₂*(1 mol CO₂/ 44 g)*(1 mol C/1 mol CO₂) = 0.01138 mol C
0.01138 mol C*(12 g/mol) = 0.13658 g C

Compute for the amount of H in the compound. The data you need to know are the following:
Molar mass of H = 1 g/mol
Molar mass of H₂O = 18 g/mol
Solution:
0.1282 g H₂O*(1 mol H₂O/ 18 g)*(2 mol H/1 mol H₂O) = 0.014244 mol H
0.014244 mol H*(1 g/mol) = 0.014244 g H

The percent composition of pure hydrocarbon would be:
Percent composition = (Mass of C + Mass of H)/(Mass of sample) * 100
Percent composition = (0.13658 g + 0.014244 g)/(<span>0.1510 g) * 100
</span>Percent composition = 99.88%

2. The empirical formula is determined by finding the ratio of the elements. From #1, the amounts of moles is:

Amount of C = 0.01138 mol
Amount of H = 0.014244 mol

Divide the least number between the two to each of their individual amounts:
C = 0.01138/0.01138 = 1
H = 0.014244/0.01138 = 1.25

The ratio should be a whole number. So, you multiple 4 to each of the ratios:
C = 1*4 = 4
H = 1.25*4 = 5

Thus, the empirical formula of the hydrocarbon is C₄H₅.

3. The molar mass of the empirical formula is

Molar mass = 4(12 g/mol) + 5(1 g/mol) = 53 g/mol
Divide this from the given molecular weight of 106 g/mol
106 g/mol / 53 g/mol = 2
Thus, you need to multiply 2 to the subscripts of the empirical formula.

Molecular Formula = C₈H₁₀

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<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

Decomposition is a type of chemical reaction in which larger compound breaks down into two or more smaller compounds.

AB\rightarrow A+B

Double displacement reactions is defined as the chemical reaction in which exchange of ions takes place.

AB+CD\rightarrow AD+CB

Synthesis reaction is a type of reaction in which two or more smaller compounds combines to form a single large compound.

A+B\rightarrow AB

Single displacement reaction is a type of reaction in which a more reactive metal displaces a less reactive metal from its chemical reaction.

A+BC\rightarrow AC+B

In stomach, an acid is present known as hydrochloric acid and to neutralize its effect, antacid is taken which has CaCO_ as a component.

The reaction between HCl and CaCO_3 is a type of neutralization reaction and it is a type of double displacement reaction.

The equation between the two follows:

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Hence, the correct answer is Option B.

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Answer:

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Explanation:

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