If the reaction started with 32g of Sulfur and 56 grams of Iron, then mass of produced FeS is 88 grams.
<h3>What is the relation between mass & moles?</h3>
Relation between the mass and moles of any substance will be represented as:
n = W/M, where
- W = given mass
- M = molar mass
Moles of Fe = 56g / 56g/mol = 1 mol
Moles of S = 32g / 32g/mol = 1 mol
Given chemical reaction is:
Fe + S → FeS
From the stoichiometry of the reaction same moles of iron and sulfur are required to produce equal moles of iron sulfide. Means 1 mole of iron produces 1 moles of iron sulfide and mass of iron sulfide will be calculated as:
W = (1mol)(88g/mol) = 88g
Hence required mass of iron sulfide is 88 grams.
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Answer:
156 Hydrogen atoms
Explanation:
<u>Any acyclic alkane has a molecular formula that can be expressed as</u>:
CₙH₂ₙ₊₂
Where <em>n</em> is any integer and the number of carbon atoms. For example, Propane has 3 carbon atoms, this means it would have [2*3+2] 8 hydrogen atoms, resulting with a formula of C₃H₈.
An acyclic alkane with 77 carbon atoms would thus have:
2*77 + 2 = 156 hydrogen atoms
Answer:
a physical change does not change the composition (what it's made of) as a chemical change would.
Answer is: mass of calcium hydroxide is 46.98 grams.
Balanced chemical reaction: CaO + H₂O → Ca(OH)₂.
m(CaO) = 35.55 g.
n(CaO) = m(CaO) ÷ M(CaO).
n(CaO) = 35.55 g ÷ 56 g/mol.
n(CaO) = 0.634 mol; limiting reactant.
m(H₂O) = 125 mL · 1.000 g/mL.
m(H₂O) = 125 g.
n(H₂O) = 125 g ÷ 18 g/mol.
n(H₂O) = 6.94 mol.
From chemical reaction: n(CaO) : n(Ca(OH)₂) = 1 : 1.
n(Ca(OH)₂) = 0.634 mol.
m(Ca(OH)₂) = 0.634 mol · 74.1 g/mol = 46.98 g.
16 grams.
Looking at the reaction equation, it's evident that for each mole of HBr
consumed, 1 mole of CO2 will be produced. So let's calculate the molar mass
of HBr and CO2 first.
Atomic weight hydrogen = 1.00794
Atomic weight bromine = 79.904
Atomic weight carbon = 12.0107
Atomic weight oxygen = 15.999
Molar mass HBr = 1.00794 + 79.904 = 80.91194 g/mol
Molar mass CO2 = 12.0107 + 2*15.999 = 44.0087 g/mol
Moles HBr = 30 g / 80.91194 g/mol = 0.370773461 mol
Grams CO2 = 0.370773461 mol * 44.0087 g/mol = 16.317258 g
Rounding to 2 significant digits gives 16 grams.