All categories

4 years ago

Which organism was used to re-evaluate its position in

Biology

1 answer:

marta [7]4 years ago

6 0

Answer:

Fungi

Explanation:

Fungi is a eukaryotic organism that is re-evaluating its position in the tree of life.

Fungi are closely related to the animal kingdom in comparison to the plant kingdom. Because of the presence of the chitin in their cell walls, fungi is different from plant, bacteria, and protists. But fungi have cell wall while animal cells do not contain cell wall, so not classified as animals.

So, fungi is re-evaluating its position in the tree of life and in present there is a individual kingdom for fungi.

You might be interested in

The vertebrate endoskeleton differs from an arthopod's exoskeleton because it

Vlada [557]

The vertebrate endoskeleton is internal while an arthropod's exoskeleton is not

8 0

4 years ago

Considering the same population of cats as in Part A, what is the expected frequency of each genotype (TLTL, TLTS, TSTS ) based

zaharov [31]

Answer:

P = f(TLTL) = 0,16

H = f(TLTS) = 0,48

Q = f(TSTS) = 0,36

Explanation:

Hello!

The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values can vary between 0 (absent allele) and 1 (fixed allele).

The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.

In this case, let's say:

f(TL) = p

f(TS) = q

p + q = 1

Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:

TL= 0,4

TS= 0,6

Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.

P = f(TLTL)

H = f(TLTS)

Q = f(TSTS)

Also P + H + Q = 1

And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:

$p^{2} = f(TLTL)$

$2pq = f(TSTL)$

$q^{2} = f(TSTS)$

So, if the population is in balance:

$P = p^{2}$

$H = 2pq$

$Q = q^{2}$

Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:

$f(TLTL) = P = p^{2} = 0,4^{2} = 0,16$