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kupik [55]
3 years ago
8

What is the average rate of change for this quadratic function for the interval from x = 0 to x = 2? A. –2 B. 2 C. 4 D. –4

Mathematics
2 answers:
erik [133]3 years ago
8 0
<h3><u>Answer:</u></h3>

Hence,the average rate of change for this quadratic function for the interval from x = 0 to x = 2 is:

-2

<h3><u>Step-by-step explanation:</u></h3>

<em>The average rate of a function f(x)  from x=a to x=b is given as:</em>

<em>=\dfrac{f(b)-f(a)}{b-a}</em>

Clearly we are asked to find the average rate of change from x=0 to x=2.

i.e. a=0 and b=2

Also, from the graph it could be observed that:

f(0)=1

and f(2)=-3

Hence, the average rate of change is calculated as:

=\dfrac{f(2)-f(0)}{2-0}\\\\=\dfrac{-3-1}{2-0}\\\\=\dfrac{-4}{2}\\\\=-2

Hence,the average rate of change for this quadratic function for the interval from x = 0 to x = 2 is:

-2

Alla [95]3 years ago
4 0

Answer: -2


Step-by-step explanation:


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2 years ago
Please help with these math questions
Tanya [424]
1.
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a=a
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a=16.4924
D is answer



2. same thing
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3.
one way is to plug them in
remember that hypotonuse is longest side
A. 7^2+24^2=25^2, is that true?, yes it is treu
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1. D
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4 0
3 years ago
LINEAR EQUATIONS PLZ HELP BRAINLIEST AND EXTRA POINTS!!!
Oliga [24]

Answer:


1) B) a = 14

2)D) x = -11

3)B) x = 8

4)A) 250 = 3c-20

5)D)8

6)B), C), D)

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9)Sarah = 40 years

Sarah = 5/4 x Tanya

40 = 5/4 x Tanya's age

Therefore Tanya's age is 32 years old


Hope this helps you!


4 0
2 years ago
Read 2 more answers
5 ports Use absolute value to express the distance between -12 and -15 on the number line. |-12 - (-15) = -27​
zloy xaker [14]

Answer:

Distance = 3

Step-by-step explanation:

Given

-12 and -15

Required

Solve the difference

The question you posted included the solution. However, the solution is incorrect;

The absolute difference is represented as:

Difference = \vert a - b \vert

In this case:

a = -12

b = -15

So, the distance is calculated as:

Distance = |-12 - (-15)|

Open bracket

Distance = |-12 +15|

Distance = |3|

Distance = 3

3 0
3 years ago
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