<span>A polygon has an angle sum of 360°, and each angle measures 90°. Let's find our what is the polygon.
=> 360 degrees polygon with 90 degree measure for each angles.
=> 360 degrees / 90 degrees = 4
Therefore the polygon is a square.</span>
X=-7 AB=-72
steps
since m is a midpoint, AM and MB are congruent so you set the two equations equal to each other, 4x-9=5x-3/3( is this a typo? bc 3/3 is 1)
subtract 4x from both sides m, -8=x-1
add 1 to both sides
x=-7
then plug -7 in for x 4(-7)-8=-36
since the two segments are congruent u do -36 x 2= -72
$750000 for all 10 years and $375000 for just ten years
Parameterize
by

with
and
. Take a normal vector to
,

which has norm

Then the integral of
over
is

