The given compound is being synthesized by condensing
Acetone and
Pivaldehyde (Trimethylacetaldehyde).
First Acetone is treated with
Base, the base abstracts the mildly acidic proton present at alpha position to carbonyl group. The resulting specie called
enolate act as a nucleophile and attacks on highly reactive aldehyde which upon
dehydration yields the
Aldol Product. The Reaction is as follow,
Answer:
The answer is 2.660 mol/l
Explanation:
Given: n= 0.0665, v= 25.00ml
Required: C
C (molarity)= n (of solute)/ v (of solvent) [ standard unit: mol/l]
First convert volume of solvent in its standard unit, i.e. litres(L)
v= 25.00ml/1000= 0.02500L
C = 0.0665 mol / 0.02500 L= 2.660 mL (In proper significant digits i.e. 4 sigdigs)
Therefore, The molarity of the sulfuric acid is 2.660 mol/L :)
Answer:
frogs, fish and aquatic (water-dwelling) insects
Explanation: