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3 years ago

$2300 at 7% for 9 years

Mathematics

2 answers:

ruslelena [56]3 years ago

6 0

Answer:

If simple interest, 2300+(2300*0.07)*9

If compound, 2300+(2300*0.07)^9

serious [3.7K]3 years ago

6 0

Answer:

I don't know if this is what your looking for, but 7% of $2,300 for 9 years is $1,449

Step-by-step explanation:

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Let x ∼ bin(9, 0.4). find

Kobotan [32]

A.
$\mathbb P(X>6)=\mathbb P(X=7)+\mathbb P(X=8)+\mathbb P(X=9)$
$=\dbinom97(0.4)^7(1-0.4)^{9-7}+\dbinom98(0.4)^8(1-0.4)^{9-8}+\dbinom99(0.4)^9(1-0.4)^{9-9}$
$\approx0.025$

b.
$\mathbb P(X\ge2)=1-\mathbb P(X$
$=1-\dbinom90(0.4)^0(1-0.4)^{9-0}-\dbinom91(0.4)^1(1-0.4)^{9-1}$
$\approx0.929$

c.
$\mathbb P(2\le X$
$=\dbinom92(0.4)^2(1-0.4)^{9-2}+\dbinom93(0.4)^3(1-0.4)^{9-3}+\dbinom94(0.4)^4(1-0.4)^{9-4}$
$\approx0.663$

d.
$\mathbb P(2$
$=\dbinom93(0.4)^3(1-0.4)^{9-3}+\dbinom94(0.4)^4(1-0.4)^{9-4}+\dbinom95(0.4)^5(1-0.4)^{9-5}$
$\approx0.669$

e.
$\mathbb P(X=0)=\dbinom90(0.4)^0(1-0.4)^{9-0}\approx0.01$

f.
$\mathbb P(X=7)=\dbinom97(0.4)^7(1-0.4)^{9-7}\approx0.021$

g, h.
For $X\sim\mathcal B(n,p)$ , recall that $\mathbb 
E[X]=\mu_X=np$ and $\mathbb V[X]={\sigma_X}^2=np(1-p)$ . So

$\mu_X=9(0.4)=3.6$
${\sigma_X}^2=9(0.4)(0.6)=2.16$

6 0

3 years ago

What is the value of x:

notsponge [240]

Answer:

100

Step-by-step explanation:

In a 45-45-90 triangle, the hypotenuse is always larger than either of the legs by a factor of $\sqrt{2}$ . x is therefore:

$100\sqrt{2}\div \sqrt{2}=100$

Hope this helps!

6 0

4 years ago

best rentals charges a daily fee plus a mileage fee for renting its cars. barney was charged $159 for 3 days and 300 miles, whil

Vesnalui [34]

$289 is better because its cheaper per mile

6 0

3 years ago

Julian has to read 4 articles for school. He has 8 nights to read them. He decides to read the same number of articles each nigh

daser333 [38]

Answer:

a. He will have to read half an article per night

b. Fraction of the reading assignment read each night = $\frac{0.5}{4}=\frac{1}{8}$

Explanation:

Part a:

We are given that:

number of articles to read = 4 articles

number of nights = 8 nights

To get the number of articles that he should read per night, we will simply divide the the number of articles by the number of nights

Therefore:

number of articles to read per night = $\frac{4}{8}=\frac{1}{2}$ articles per night

Part b:

Now, we know that he will read half an article each night from a total of 4 articles

To get the fraction of the reading assignment read each night, we will divide the number of articles read each night by the total number of assignments

Therefore:

Fraction of the reading assignment read each night = $\frac{0.5}{4}=\frac{1}{8}$

Hope this helps :)

5 0

3 years ago

What is the value of 3ab+ 5b - 6 when a = - 1and b = 3

Fantom [35]

Answer:

the answer is 0

4 0

3 years ago

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