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kolezko [41]
3 years ago
11

If y is directly proportional to x and y = 5 when x =2, what is the value of y when x=6

Mathematics
2 answers:
sammy [17]3 years ago
7 0

Answer:

y=15

Step-by-step explanation:

The formula for direct variation is

y = kx

5 =k*2

Solve for k

Divide by 2

5/2 = k

y = 5/2 x

Now we substitute x=6

y = 5/2(6)

y = 15

Tasya [4]3 years ago
4 0

Answer:

y = 15

Step-by-step explanation:

If the variables are directly proportional, increasing one by a factor of 3 will mean the other one also increases by a factor of 3.

6 is 3 times 2, so the value of y will be 3 times 5, or 15.

___

You can write the relation as a proportion:

y/x = 5/2 = ?/6

Multiplying by 6 gives ...

(5/2)·6 = ? = 15

___

Or, you can bother with an equation relating x and y:

y = kx

5 = k·2 . . . plug in the given values and solve for k

5/2 = k . . . divide by 2

Then ...

y = (5/2)·6 = 15 . . . . same as the proportion, above.

If you rearrange this to y = 5·(6/2) then you see the relation described at the beginning of this solution. The new value of y is the old value multiplied by the factor by which x changes.

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The sum of two numbers is 11 and their product is 18. Find the numbers.
Vanyuwa [196]

Answer: the numbers are 9 and 2

Step-by-step explanation:

Let the numbers be a and b

a + b = 11.........equation 1

ab = 18.......equation 2

Multiply equation 1 by a

a ^2 + ab = 11a.......equation 3

Substitute the value of ab from equation 2 into equation 3

a ^2 + 18 = 11a

a^2 - 11a + 18 = 0

(a-9) x (a-2) = 0

If a = 9, then b =2

I hope this helps, please mark as brainliest answer.

3 0
3 years ago
Help me with this question pls
Mandarinka [93]
1/6 was not eaten

Hope this helps

4 0
3 years ago
Read 2 more answers
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EastWind [94]
The second question is biased
3 0
4 years ago
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How many hundredths in 45.972
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6 0
3 years ago
find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.​
DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}

Or, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}

Or,  The surface area of right regular hexagonal pyramid = 23.38 + 9 × \frac{171}{4}

∴  The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So,  The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

6 0
4 years ago
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