Explain why you can use πr2 to find the area of the base of a cone

1 answer:

8 0

The base of a cone is a circle.

The area of a circle is $\pi r^2$ .

Thus, the area of the base of a cone $\pi r^2$ .

The derivation of the formula for the area of a circle involves a bit of calculus, but if you'd like, I can walk you through it.

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The lowest temperature ever recorded at Oymyakon in Russia was 96.2°F below 0°F. The lowest temperature ever recorded at Prospec

Alekssandra [29.7K]

Answer:

Thermometer reading of the lowest recorded temperature at Oymyakon was -96.2° F

Thermometer reading of the lowest recorded temperature at Prospect Creek was -80° F

Step-by-step explanation:

If the temperature is x° F below 0° F then the thermometer reading is -x° F

It is given that the Lowest temperature recorded at Oymyakon in Russai was 96.2°F below 0°F

So the thermometer reading of the lowest recorded temperature at Oymyakon was -96.2° F

Also it is given that the Lowest temperature recorded at Prospect Creek in Alaska was 80°F below 0° F

So the thermometer reading of the lowest recorded temperature at Prospect Creek was -80° F

7 0

3 years ago

A flying squirrel lives in a nest that is 9 meters high in a tree. To reach a fallen acorn that is 4 meters from the base of the

Luba_88 [7]

Answer:

Flying squirrel have to glide is for 9.8 meters approximately.

Step-by-step explanation:

Here we can use Pythagoras theorem.

Height is 9 , base is 4.

We need to find the hypotenuse measure.

So, let's use Pythagoras theorem $a^{2} +b^{2}= c^{2}$

Plug in a as 9 and b 4.

$9^{2} +4^{2}=c^{2}$

Simplify the left side of the equation

$81+16=c^{2}$

$97=c^{2}$

Take square root on both sides.

c=9.8 meters.

6 0

2 years ago

I don’t really get this question so if anyone knows it please help

Mars2501 [29]

Answer:

$116.82\:\text{square inches}$

Step-by-step explanation:

The window consists of a large square and 4 smaller triangles on the outside. The side length of this square is marked as 10, and therefore the area of this square is $10^2=100\:\mathrm{in^2}$ .

The area of a triangle is given by $\frac{1}{2}\cdot b\cdot h$ . Since the problem states that the overlapping squares are congruent, both legs of the triangle will be $2.9$ and intersect at a $90^{\circ}$ angle.