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3 years ago

Explain why you can use πr2 to find the area of the base of a cone

1 answer:

8 0

The base of a cone is a circle.

The area of a circle is $\pi r^2$ .

Thus, the area of the base of a cone $\pi r^2$ .

The derivation of the formula for the area of a circle involves a bit of calculus, but if you'd like, I can walk you through it.

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56% in its simplest form

masha68 [24]

Fourteen over twenty five
hoped that helped<span />

7 0

4 years ago

A digital scale reports a 10 kg weight as weighing 8.975 kg

sergiy2304 [10]

That question is accompanied by these answer choices:

<span>A. The scale is accurate but not precise.
B. The scale is precise but not accurate.
C. The scale is neither precise nor accurate.
D. The scale is both accurate and precise.

Then you need to distinguish between accuracy and precision.

Accuracy refers to the closeness of the measure to the real value, while precision, in this case, refers to the level of significant figures that the sacle report.

The fact that the scale reports the number with 4 significant figures means that it is very precise, but the fact that the result is not so close to the real value as the number of significan figures pretend to be, means that the scale is not accurate.

So, the answer is that the scale is precise but not accurate (the option B</span>

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3 years ago

Explain how algebra tiles represent like terms and zero pairs

Leokris [45]

If there is a negative tile and a positive tile, it creates a zero pair.
Like terms can occur with the same variables (except for terms with exponents)

6 0

3 years ago

When solving a system of two linear equations

soldier1979 [14.2K]

Answer:

When both equations have the same slope, but not the same y-intercept, they'll be parallel to each other and no intersections means no solutions. When both equations have different slopes than regardless of the y-intercept they'll intersect for certain, therefore it has exactly one solution.

Step-by-step explanation:

Got this from google hope it helps

7 0

3 years ago

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

3 0

3 years ago