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3 years ago

I need to find the slope for these lines please help !!!

Mathematics

1 answer:

astraxan [27]3 years ago

5 0

The green line passes through the points (0, -3) and (9, 0). Compute the slope:

(0 - (-3)) / (9 - 0) = 3/9 = 1/3

(That is, going left to right, divide the difference in the <em>y</em> coordinates by the difference in the <em>x</em> coordinates.)

Parallel lines have the same slope. So both answers are 1/3.

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densk [106]

I believe it is 128. I may be wrong but if there are 384 tickets sold and there were 2 times more student tickets sold than adult then there are 128 tickets lift over to be adult tickets

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3 years ago

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This is my spring break hw but I don’t understand this question

vladimir1956 [14]

5 + 20 = 25 and that’s the answer

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3 years ago

Please help me with these 2 questions

STatiana [176]

Answer:

#1.) x = 7

Step-by-step explanation:

#1.) Here, AB = BC because they are tangents that meet at a common endpoint

so 5x + 11 = 3x + 25

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3 years ago

89 (54x − 36) + 2 = −3/4 (−40 + 16x) + 90xsolve for x

Amiraneli [1.4K]

Hey! Just in case you have to show your work.

89(54x-36)+2=-3/4(-40+16x)+90x

4806x-3204+2=-3/4×4(-10+4x)+90x

4806x-3202=30-12x+90x

4806x-78x=30+3202

4728x=3232

3232÷4728=

X=404/591

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3 years ago

Find the domain of the function y = 3 tan(23x)

solmaris [256]

Answer:

$\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

In other words, the $x$ in $f(x) = 3\, \tan(23\, x)$ could be any real number as long as $x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)$ for all integer $k$ (including negative integers.)

Step-by-step explanation:

The tangent function $y = \tan(x)$ has a real value for real inputs $x$ as long as the input $x \ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

Hence, the domain of the original tangent function is $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

On the other hand, in the function $f(x) = 3\, \tan(23\, x)$ , the input to the tangent function is replaced with $(23\, x)$ .

The transformed tangent function $\tan(23\, x)$ would have a real value as long as its input $(23\, x)$ ensures that $23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

In other words, $\tan(23\, x)$ would have a real value as long as $x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right)$ .

Accordingly, the domain of $f(x) = 3\, \tan(23\, x)$ would be $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

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2 years ago