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Likurg_2 [28]
3 years ago
7

PLEASE HELP! The table shows the number of cans of soup shipped in different numbers of boxes.

Mathematics
2 answers:
Nuetrik [128]3 years ago
7 0

c = 48b_96 = 48(2)_96 = 96

so c=48b

mel-nik [20]3 years ago
5 0
The equation that expresses the relationship between the number of boxes, b and the number or cans, c would be c = 48b. This is because the number or cans shipped would be the dependent variable to the problem as it is dependent on the number or boxes that ship along with. So if one ships 2 boxes then the number of cans that would be shipped would need to match the final output of cans which is 96, and using the equation, c = 49b it does.

c = 48b
96 = 48(2)
96 = 96.

Technically the first option will also be correct but usually the variable in an algebraic expression comes after the coefficient.
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Simplify the expression (8x^3y^2/4a^2b^4)^-2
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3 0
3 years ago
The parents' club will need 100 of the same item for international night. They have a budget of $250. The choices are 100 baseba
Nuetrik [128]

Answer:

The parents' club can afford to buy 100 Baseball hats or 100 sports bottles.

Step-by-step explanation:

Given:

Item to be bought = 100

Total Budget = $250

Cost of each Baseball Hat = $2.45

Cost of each sports bottles = $2.50

Cost of each flag = $2.75

We need to find which items can they afford to buy.

Solution:

each Baseball Hat = $2.45

100 Baseball Hat = Cost of 100 Baseball Hat

Using Unitary method we get;

Cost of 100 Baseball Hat  = 2.45\times 100 =\$245

each sports bottles = $2.50

100 sports bottles = Cost of 100 sports bottles

Using Unitary method we get;

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each flag = $2.75

100 flags = Cost of 100 flags

Using Unitary method we get;

Cost of 100 flags  = 2.75\times 100 =\$275

Hence from above we can see that;

Cost of 100 Base ball hat and 100 sports bottles are within the budget while Cost of 100 flags exceed the budget.

So we can say that;

The parents' club can afford to buy 100 Baseball hats or 100 sports bottles.

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