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Likurg_2 [28]
3 years ago
7

PLEASE HELP! The table shows the number of cans of soup shipped in different numbers of boxes.

Mathematics
2 answers:
Nuetrik [128]3 years ago
7 0

c = 48b_96 = 48(2)_96 = 96

so c=48b

mel-nik [20]3 years ago
5 0
The equation that expresses the relationship between the number of boxes, b and the number or cans, c would be c = 48b. This is because the number or cans shipped would be the dependent variable to the problem as it is dependent on the number or boxes that ship along with. So if one ships 2 boxes then the number of cans that would be shipped would need to match the final output of cans which is 96, and using the equation, c = 49b it does.

c = 48b
96 = 48(2)
96 = 96.

Technically the first option will also be correct but usually the variable in an algebraic expression comes after the coefficient.
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Taylor's computer randomly generate numbers between 0 and 4, as represented by the given uniform density curve.
MrRa [10]

12.5% is the percentage of numbers randomly generated by Taylor's computer that is less than 0.5.

An illustration of a numerical distribution with continuous results is a density curve. A density curve is, in other words, the graph of a continuous distribution. This implies that density curves can represent continuous quantities like time and weight rather than discrete events like rolling a die (which would be discrete). As seen by the bell-shaped "normal distribution," density curves either lie above or on a horizontal line (one of the most common density curves).

The percentage of numbers randomly generated by Taylor's computer are less than 0.5 is given by

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3 0
2 years ago
The population for Gulch Dry has been declining according to the function P(t)= 8000. 2^-t/29 where t is the number of years sin
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A)

\bf 1990-1910=80\leftarrow t
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P(t)=8000(2)^{-\frac{t}{29}}\implies P(80)=8000(2)^{-\frac{80}{29}}
\\\\\\
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and surely you know how much  that is.

b)

\bf P(t)=125\\\\\\  125=8000(2)^{-\frac{t}{29}}\implies \cfrac{125}{8000}=2^{-\frac{t}{29}}\implies \cfrac{1}{64}=2^{-\frac{t}{29}}
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\textit{now we take log to both sides}
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log\left( \frac{1}{64} \right)=log\left( 2^{-\frac{t}{29}} \right)\implies log\left( \frac{1}{64} \right)=-\frac{t}{29}log\left( 2 \right)
\\\\\\
log\left( \cfrac{1}{64} \right)=-\cfrac{tlog(2)}{29}\implies \cfrac{-29log\left( \frac{1}{64} \right)}{log(2)}=t\implies 174=t

since in 1910 t = 0, 174 years later from 1910, is 2084, so in 2084 they'll be 125 exactly, so the next year, 2085, will then be the first year they'd fall under that.
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